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help needed in Deriving Inverse Trigonmetric Functions (Not urgent this time :D)

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SGVaibhav:
awww

reached

dy/dx = 1 / (x .  root (x^2 - 1) )

lol hope u got that part
now thinking how to proceed.
if i multiply the whole thing by x^2 - 1 , then the root still stays.
if i multiply the whole thing by the root of x^2 ....., then the root comes above

SGVaibhav:
w8

i checked my book now, and this is the final answer,

except the modulus part exists for x.
how does the modulus come ???
need help now

Tyserius:
Hmm I saw that too. Lemme think about the modulus part :) Gimme a while.

Tyserius:

--- Quote from: sgvaibhav on November 10, 2009, 04:12:45 pm ---w8

i checked my book now, and this is the final answer,

except the modulus part exists for x.
how does the modulus come ???
need help now

--- End quote ---

Hmmm... I think this site can help :)

http://archives.math.utk.edu/visual.calculus/3/inverse_trig.1/5.html

Tyserius:
So, do you understand it now? xD

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