fuel cells with acid electrolyte..
heres. it..
the hydrogen (H2) loses electrons.. 2H2 --> 4H+ + 4e- which travel through the circuit to the cathode and react with O2..also the H+ ions from the acid electrolyte meets the electrons and O2 at the cathode
the reaction
O2 + 4H+ + 4e- = 2H2O
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with NaOH
Then the reactions are as follows:-
At anode: 2H2 + 4OH(-) --->4H2O + 4e(-)
At cathode: O2 + 4e(-) +2H2O ---->4OH(-)
anode - the hydrogen supplied reacts with the OH- ion form NaOH and forms water and electrons. Electrons flow round the circuit (electricity) and react at the cathode with water and O2 supplied.
The OH- ions removed at the anode are replaced by those formed at the cathode.
