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IGCSE PHYSICS

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cooldude:

--- Quote from: @d!_†oX!© on November 07, 2009, 02:53:35 pm ---yaaa dts rite cooldude...
@aadi dts wat i wanna know dude...how did ya get 70 for 49 mm??????

--- End quote ---

dude!!!!!!!!!!! i also explained the second part...look!!!!!!!!!!

ill paste it for u--

1.c=0.7mm
1mm=1/0.7.c
therefore the length for which there is a temperature change=>61-12=49mm
therfore the temperature at this=>49*(1/0.7)=70.c
just do it by simple unitary method

and also since the temperature starts from 0, 70 is ur final ans but cuz the length starts from 12 so u hve to consider 12 in every calculation u make wich evry1 is trying to tell u

Ghost Of Highbury:
sry sry it shud 0 to 70

ok look..
in the range of 12 to 82

they are asking 61

61 is 49 above from 12

so for our scale which 0 to 70, we have to go 49 above from 0 = 0+49 = 49

got it?

@d!_†oX!©:
@ cooldude chill man...i've seen urs..nd i got it....i said m just looking for alternate ways...!!!stay calm man...take a deep breath in.........and out......cool??!!

@aadi u till didnt get my point man..i know till here...now how did u get 70 fro 49?? is my question.....

nid404:
okay for the second part assume the same way

so
assuming
 100o=70mm(82-12)
then xo= 61mm-12mm

x= 4900/70=70o


      

cooldude:

--- Quote from: @d!_†oX!© on November 07, 2009, 02:59:47 pm ---@ cooldude chill man...i've seen urs..nd i got it....i said m just looking for alternate ways...!!!stay calm man...take a deep breath in.........and out......cool??!!

@aadi u till didnt get my point man..i know till here...now how did u get 70 fro 49?? is my question.....

--- End quote ---

k dude, By the way just look at my last post ive told u a few things, let other ppl give their views nw

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