Qualification > Sciences
IGCSE PHYSICS
nid404:
okk
I will try my best to explain this
Given
at 0oC=12mm
& and 100oC=82mm
difference is 70. So if the reading was.....if for 0 and 70 mm, then length would have been 70/2=35mm for 50 degrees....exactly half
so when the startin point is 12oC...u will add 12 to the difference/2=47mm. I hope ur able to figure out the logic.
The length for 50 degrees would be right in the middle of 12 and 82
@d!_†oX!©:
yaa i got that 50 one like dt too...wt about the second part???
i really thing cooldude's explanation is gud...bt i really dont wanna forget it again...so pls guys try nd give me ur working ways to..so dt i have some more ways to do it nd i do not forget...
Ghost Of Highbury:
assume its from 1mm to 70mm
theyre asking 61mm but thats frm their scale, from our scale it wud be...61-12 = 49
so
70mm - 100
49mm - 70
cooldude:
nid's method is good for the first part and first part only (it is the simplest way by which u can understand this part of the q), but since u have to do the second part also which does nt hve somehting which is half way or quarter way so u hve to do it by the unitary method. if u do both parts by diff methods then u urself will get confused
@d!_†oX!©:
yaaa dts rite cooldude...
@aadi dts wat i wanna know dude...how did ya get 70 for 49 mm??????
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