Author Topic: HELP Physics ppr 3 Jun. 09  (Read 2737 times)

Offline moon

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HELP Physics ppr 3 Jun. 09
« on: November 05, 2009, 05:41:20 pm »
Plz I need help in these Questions. Q.4 a(ii), Q5 (b), Q9(b)  ???

Offline Ghost Of Highbury

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Re: HELP Physics ppr 3 Jun. 09
« Reply #1 on: November 05, 2009, 05:48:58 pm »
Q5bi ) half mass thus, 7500/2 = 3750kG

bii) power output second day = 10/100 * (3750/2 * 36) = 6750

     fraction thus, 6750/54000 = 1/8

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Offline Ghost Of Highbury

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Re: HELP Physics ppr 3 Jun. 09
« Reply #2 on: November 05, 2009, 05:52:29 pm »
9bi - A

bii - attached

red-->blue-->green-->yellow
« Last Edit: November 05, 2009, 06:15:57 pm by A@di »
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Offline Ghost Of Highbury

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Re: HELP Physics ppr 3 Jun. 09
« Reply #3 on: November 05, 2009, 05:58:52 pm »
draw the scale diagram as shown

measure the length of the diagonal and calculate the force accordingly

measure the angle

shud be

-> 5500N
--> 30o
« Last Edit: November 05, 2009, 06:11:10 pm by A@di »
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Offline moon

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Re: HELP Physics ppr 3 Jun. 09
« Reply #4 on: November 05, 2009, 06:06:58 pm »
draw the scale diagram as shown

measure the length of the diagonal and calculate the force accordingly

measure the angle

shud be

-> 5500N
--> 30o

where is the road on the drawing???

Offline moon

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Re: HELP Physics ppr 3 Jun. 09
« Reply #5 on: November 05, 2009, 06:09:10 pm »
9bi - A

bii - attached

where is the conventional current on the drawing?? here is the markscheme answer but I didn't understand it..

 (ii) For answers A and B only in (i), not C or D:
Route to resistor: correct arrow on one downwards diode and
nothing wrong on this route B1
Route from resistor: correct arrow on one downwards diode and
nothing wrong on this route

Offline Ghost Of Highbury

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Re: HELP Physics ppr 3 Jun. 09
« Reply #6 on: November 05, 2009, 06:13:10 pm »
check the diagram again. The road is marked in red.

and for the conventional current..i have made colored lines for ur better understanding.check again
« Last Edit: November 05, 2009, 06:16:21 pm by A@di »
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Offline moon

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Re: HELP Physics ppr 3 Jun. 09
« Reply #7 on: November 05, 2009, 06:25:45 pm »
but how can we draw the conventional current as specified in the mark scheme.. ???

Offline Ghost Of Highbury

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Re: HELP Physics ppr 3 Jun. 09
« Reply #8 on: November 05, 2009, 06:29:12 pm »
but how can we draw the conventional current as specified in the mark scheme.. ???

the markscheme for this question is horrible..it doesnt specify anything...it just says arrow on one downwards diode, which i have shown, rest u just continue the path as shown in my diagram.

it says "nothing wrong on this route" which states clearly that they are not mentioning any correct answer for this. It depends on the examiner. I suppose my diagram is correct.

Did u understand the rest of the quetions?
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Offline vaan

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Re: HELP Physics ppr 3 Jun. 09
« Reply #9 on: November 05, 2009, 06:54:24 pm »
can some1 help me in additional math....2002 November...paper 01....question 5.....i dont want de mark scheme answer...i want de process....

Offline moon

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Re: HELP Physics ppr 3 Jun. 09
« Reply #10 on: November 05, 2009, 06:58:34 pm »
Q5bi ) half mass thus, 7500/2 = 3750kG


Why here y the mass was halved?? although the question mentions that the speed is halved ???

Offline vaan

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Re: HELP Physics ppr 3 Jun. 09
« Reply #11 on: November 05, 2009, 07:19:28 pm »
moon...if de speed is halved den de amount of air passes is also halved...hence de is also halved...

Offline moon

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Re: HELP Physics ppr 3 Jun. 09
« Reply #12 on: November 05, 2009, 08:33:33 pm »
thank u A@di and vaan for ur help.hey, vaan u can send ur question in another topic to be seen. :)

Offline Ghost Of Highbury

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Re: HELP Physics ppr 3 Jun. 09
« Reply #13 on: November 06, 2009, 03:30:25 am »
can some1 help me in additional math....2002 November...paper 01....question 5.....i dont want de mark scheme answer...i want de process....
its a matrix one. i gotta draw 'em
having breakfast...will be back
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Offline Ghost Of Highbury

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Re: HELP Physics ppr 3 Jun. 09
« Reply #14 on: November 06, 2009, 03:30:42 am »
thank u A@di and vaan for ur help.hey, vaan u can send ur question in another topic to be seen. :)

ur welcome
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