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Author Topic: maths problem  (Read 2692 times)

Offline spookyjaransh

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maths problem
« on: November 03, 2009, 03:20:15 pm »
a gardner has 357 tulips to plant. if she plants x rows with y bulbs in each row, the equation fr the bulbs left over would be 357-xy (right?). if 10<x<20 and y>20, what r x and y ??
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Offline Ghost Of Highbury

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Re: maths problem
« Reply #1 on: November 03, 2009, 03:30:36 pm »
which past paper q is this?
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Offline holychalice

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Re: maths problem
« Reply #2 on: November 03, 2009, 03:30:54 pm »
y = 21 nd x = 17 ...
im nt sure ... is it frm a past ppr ?
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nid404

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Re: maths problem
« Reply #3 on: November 03, 2009, 03:33:44 pm »
The question seems incomplete....

The only way i thought we can solve this was by taking factors of 357

357

the only way to write 357 for x between 10 and 20 and y greater than 20 would be 17X21(since they have to be whole no.s)

hence x=17 and y=21

but i still thing there's summin missin.....

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Offline @d!_†oX!©

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Re: maths problem
« Reply #4 on: November 03, 2009, 03:34:49 pm »
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Offline spookyjaransh

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Re: maths problem
« Reply #5 on: November 03, 2009, 03:44:11 pm »
not a linear prog. question, but still thanx.....
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nid404

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Re: maths problem
« Reply #6 on: November 03, 2009, 03:51:28 pm »
It's takin time to load...I'll check and reply
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nid404

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Re: maths problem
« Reply #7 on: November 03, 2009, 03:56:17 pm »
you missed a part of the question....as i said summin is missin :D

It said find x and y such that no bulbs are left over

then 17 and 21 is correct...caue it exactly divides 357....no remainders
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Offline spookyjaransh

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Re: maths problem
« Reply #8 on: November 03, 2009, 03:57:27 pm »
oh, ya sorry.......... :P :-[
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nid404

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Re: maths problem
« Reply #9 on: November 03, 2009, 03:58:58 pm »
Quote from: spookyjaransh on November 03, 2009, 03:57:27 pm
oh, ya sorry.......... :P :-[

it's k....so u got this right?
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Offline spookyjaransh

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Re: maths problem
« Reply #10 on: November 03, 2009, 04:00:40 pm »
ya, thanx.........i was trying to get the total of 257 :-[ :-[ :-[ :-[ :-[ (not intentionally, just a little worked out now...), so thats wat was sooo confusing........ :P :P :P :P :P :P
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Offline holychalice

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Re: maths problem
« Reply #11 on: November 03, 2009, 04:02:28 pm »
heyy .. so hw did u do ?? hit and trial ?? or by sum formula ...
can sum1 confirm this answer ... cuz i think it cud be done graphically
is this a correct method ??
« Last Edit: November 03, 2009, 04:08:11 pm by M.@.N.B.i.R. »
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nid404

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Re: maths problem
« Reply #12 on: November 03, 2009, 04:08:48 pm »
no graph required......it has got to be using factors.

no graph for a 2mark question
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Offline wassup

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Re: maths problem
« Reply #13 on: November 03, 2009, 04:09:30 pm »
can ne1 explain me d b part???
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nid404

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Re: maths problem
« Reply #14 on: November 03, 2009, 04:12:48 pm »
square root of 357 is 18.89....but there can't be fraction of bulbs....In the square number of rows and bulbs will be same...hence u take root...hope u got that... So the answer would be 18...the nearest whole number lesser than the number...it can't be 19 cuz 192>357
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