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FRICTION !!!!!!!! HELP!!!!

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astarmathsandphysics:
for the 1st
>2T root 3  /2-Troot 3 /2=ma  so Troot 3 /2=ma m=maa osf ball
res vertically 2T/2+T=mg so T=2mg/3
then from first eq a=2mg/3 *root 3 /2m=groot 3 /3 =

astarmathsandphysics:
working back for the secon one I get the acceleration of the bead is 7g/4 which is impossible

astarmathsandphysics:
I can see the problem now. As the bead is moving down the string., the string is accelerating upwards so the length of time will be shorter. I have to find the acceleration of the m particle

astarmathsandphysics:
I think I have it. Solve the equations a1+a2=g
and a2=g/4 to get a1=3g/4 then string is passing through bead at 2a1+a2=7g/4 and use s=1/2at^2 with a =7g/4

nid404:
THank YoU Very MucH Sir

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