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FRICTION !!!!!!!! HELP!!!!

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nid404:
In fig m1=4m2. Pulleys are smooth and the thread is light. At t=0 system is released from rest. Find the maximum height reached by m2

astarmathsandphysics:
Will answer when i get home

nid404:

--- Quote from: astarmathsandphysics on November 02, 2009, 07:22:26 am ---Will answer when i get home

--- End quote ---

k thank you

astarmathsandphysics:
In fig m1=4m2. Pulleys are smooth and the thread is light. At t=0 system is released from rest. Find the maximum height reached by m2

since m1 has two strings attached it has half the acc
4mg-2T=2ma  (1) for m1
T-mg=ma    (2) for m2
(1)+2*(2)
2mg=4ma a=g/2
fpor m1 a=g/4=2.45 v^2=u^2+2as v2=0+2*9.8/4*0.2=0.98 v=sqrt(0.98)=0.99
The speed of m2 is twice the speed of m1 ie 1.98
after m1 stops m2 takes on acceleration -g v^2=u^2+2as s=(0-3.96)/2*9.8=0.2
height reached=0.4+0.2=0.6

nid404:

--- Quote from: astarmathsandphysics on November 02, 2009, 08:18:17 am ---In fig m1=4m2. Pulleys are smooth and the thread is light. At t=0 system is released from rest. Find the maximum height reached by m2

since m1 has two strings attached it has half the acc
4mg-2T=2ma  (1) for m1
T-mg=ma    (2) for m2
(1)+2*(2)
2mg=4ma a=g/2
fpor m1 v^2=u^2+2as v2=0+2*9.8/2*0.2=1.96 v=sqrt(1.96)=1.4
after m1 stops m2 takes on acceleration -g v^2=u^2+2as s=(0-1.96)/2*9.8=0.1
height reached=0.2+0.1=0.3



--- End quote ---

answer is 6.6 cm ???

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