Author Topic: Add. math!! dude slvri/astar/aadi/sam nebody help..!!!!!  (Read 22762 times)

Offline Ghost Of Highbury

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #165 on: November 12, 2009, 04:06:37 pm »
abbe yedhe.

use x = -b (+-) b^2 - 4ac / 2a

bas! khatam!
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Offline ~~~~shreyapril~~~~

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #166 on: November 12, 2009, 04:08:20 pm »
k!!
and just find x!!
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Offline Ghost Of Highbury

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #167 on: November 12, 2009, 04:12:51 pm »
ok lemme solve it

y = 2x^2 - 8x + 5 = 2(x-2)^2  -3

solve for x direcftly

y + 3 = 2(x-2)^2

(x-2)^2 = y+3 /2

x-2 = sqrt(\frac{y+3}{2}

x = sqrt(\frac{y+3}{2} +2

g-1 (x) = 2 + sqrt(\frac{x+3}{2} +2
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Offline ~~~~shreyapril~~~~

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #168 on: November 12, 2009, 04:13:49 pm »
tks dude!! ;)
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Offline vaan

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #169 on: November 12, 2009, 04:16:52 pm »
i know its a complicated way of showin....but im new so not dat much experienced....

u found perfect square in  (i)...
use dat 1 2 find de g-1
(i) =2(X-2)2+1....
let g(x)= y
y=2(x-2)2 +1...
(y-1)/2= (x-2)2...
{(y-1)/2}1/2= (x-2)...
[{(y-1)/2}1/2]+2=x...
hence g-1(x)=[{(x-1)/2}1/2]+2...
NOW PUT K VALUE....K=2...
g-1(2)=9/4

Offline vaan

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #170 on: November 12, 2009, 04:18:50 pm »
aadi how u put dat "ROOT OVER"

Offline ~~~~shreyapril~~~~

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #171 on: November 12, 2009, 04:19:57 pm »
i know its a complicated way of showin....but im new so not dat much experienced....

u found perfect square in  (i)...
use dat 1 2 find de g-1
(i) =2(X-2)2+1....
let g(x)= y
y=2(x-2)2 +1...
(y-1)/2= (x-2)2...
{(y-1)/2}1/2= (x-2)...
[{(y-1)/2}1/2]+2=x...
hence g-1(x)=[{(x-1)/2}1/2]+2...
NOW PUT K VALUE....K=2...
g-1(2)=9/4
i guess it must be -3
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Offline Ghost Of Highbury

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #172 on: November 12, 2009, 04:21:19 pm »
its latex

click on the pi symbol

and type in sqrt(watever u want to type)

like this

sqrt(watever u want to type)

@shrey - what guess!, it has to be -3 @vaan - dude, good method,  but check ur complete the square thingy its not +1 its -3
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Offline @d!_†oX!©

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #173 on: November 12, 2009, 04:22:43 pm »
sqrt(u mean like this??)

...
AAL IZZ WELL!!! ;)

Offline Ghost Of Highbury

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #174 on: November 12, 2009, 04:26:32 pm »
yes
there are many more things with latex

u can use integration, fraction symbols and stuff

\int sqrt(\frac{hi}{bye})
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Offline ~~~~shreyapril~~~~

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #175 on: November 12, 2009, 04:27:03 pm »
do not spoil my thread!!
i amy ban you  :P
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Offline .......dA dEviL.....

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #176 on: November 12, 2009, 04:45:47 pm »
Yo banana head..datz y u made me cl ya..u punk..m so kickin u A** 2mrw...n 1 mo thng da answr iz  -3 ...watch wat u doin...n if u gt ne probz..gime a ring..:D:D..

Offline vaan

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #177 on: November 12, 2009, 06:48:52 pm »
Yo banana head..datz y u made me cl ya..u punk..m so kickin u A** 2mrw...n 1 mo thng da answr iz  -3 ...watch wat u doin...n if u gt ne probz..gime a ring..:D:D..



hey b4 u ans i already understood how2 do it...u cant take de cradit...molla....kobutar..aichana ami chi na ja tui aishob nam use korish na....VALO KORA MATHAR VITOR DUKA...

Offline Saladin

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Re: Add. math!! dude slvri/astar/aadi/nebody help..!!!!!
« Reply #178 on: November 12, 2009, 06:59:04 pm »
hey let ppl hav some fun...

u guys especially Shrey talk a lot on mine....

i dont mind dat much

its just playful.

Offline Ghost Of Highbury

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divine intervention!