MATH HELP...!! URGENT...

[**!!superexcited!!!**]

Can any1 plz solve d question attatched......:

[Saladin]

n=5/3

u hav to use log, thats how i did it....

i cant explain...

[Deep]

32^(1/n) = 8
Using log,
(1/n)lg32 = lg8
(1/n) = lg8/lg32
n = 1/(lg8/lg32)
   = 5/3

[**!!superexcited!!!**]

n=5/3

u hav to use log, thats how i did it....

i cant explain...

hey the dude... Can u pleeeeeez type in the operation u use for log....

[**!!superexcited!!!**]

Thanks...

[**!!superexcited!!!**]

 

32^(1/n) = 8
Using log,
(1/n)lg32 = lg8
(1/n) = lg8/lg32
n = 1/(lg8/lg32)
   = 5/3

[**!!superexcited!!!**]

Hey do u hv to use log for quests like   32 raised to n = 2

[Deep]

32 = 2^5

so 32^2 = 2^(5*2)
            = 2^10

[**!!superexcited!!!**]

 

32 = 2^5

so 32^2 = 2^(5*2)
            = 2^10

[**!!superexcited!!!**]

32 = 2^5

so 32^2 = 2^(5*2)
            = 2^10

Hey wait a min, I dint get that..

[**!!superexcited!!!**]

this is d quest...

[astarmathsandphysics]

That is what i get.

[Ghost Of Highbury]

32 = 2^5

2^5n = 2

5n = 1

n = 1/5

[**!!superexcited!!!**]

32 = 2^5

2^5n = 2

5n = 1

n = 1/5

From wer do u get 5??   Can we use log for this question???

[**!!superexcited!!!**]

Cant see anythin...

That is what i get.