Author Topic: Quadratics query  (Read 820 times)

Offline spiderman

  • SPIDERMAN
  • SF Immigrant
  • **
  • Posts: 64
  • Reputation: 792
Quadratics query
« on: October 16, 2009, 03:38:15 am »
Hey guys,

pls can ull help me out with this question......

a) Express 9x^2+12x+7 in the form (ax+b)^2 + c where a,b and c are constants whose values are to be found.


b) Find the set of values taken by 1/(9x^2+12x+7) for real values of x.


Someone pls helppppp. ???
Always hangin around ur neighbourhood..........

nid404

  • Guest
Re: Quadratics query
« Reply #1 on: October 16, 2009, 07:56:31 am »
a) is completing the square method

so it is (3x+2)2+3

b) 0<f(x)<=1/3
this is becuz no value of f(x) can be less than zero....since a negative x will be squared to give a positive value...
the greatest value of f(x) would be when denominator is least...this will be possible only when denominator is 3 and bracket is 0. hence 1/3

Offline spiderman

  • SPIDERMAN
  • SF Immigrant
  • **
  • Posts: 64
  • Reputation: 792
Re: Quadratics query
« Reply #2 on: October 19, 2009, 07:23:00 am »
Thanks a lot
Always hangin around ur neighbourhood..........

nid404

  • Guest
Re: Quadratics query
« Reply #3 on: October 21, 2009, 11:54:14 am »