Call the triangle staring from a corner x, a tiangle on a side z and the one in the middle y
The whole area =4x+y+4z=1
Put a compass on the corner of the square and form part (1/4) of a circle. The area of that part is 3x+y+2z=
TDo this again but on the opposite side of the square to obtain another quarter of a ficle. The difference beween these two quarters and the area of the square istwo triangles and the middle from diagonal to diagonal ie 2x+y=
Solve these equations simultaneously.
Will try and finish it when I get home in a few hours