Qualification > Math

maths help!!

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Ghost Of Highbury:
the third one is 0...

a=0 b=0 c=0

nid404:

--- Quote from: mousa on September 25, 2009, 08:38:09 am ---ooohh1!! nid,  chem practical?

--- End quote ---

yeah....why can't they name the damn things with the name of the substance rather than complicate it....FA1, FA2....F**k u...

and here's the m1m2=-1 proof

Slope of a given line= tan theta (delta y/ delta X)
So if there are two slopes m1 and m2
1 having inclination of theta, then m1=tan theta....Other line has inclination pi/2 + theta......i hope you can visualize this
then m2= tan (pi/2 +theta)=-cot theta(-1/tan theta) => m1m2=-1

nid404:
 let p,with coorinates (p,q), be a fixed point on the 'curve ' with equation y=mx+c and let Q with coordinates (r,s), be any other point on y=mx+c . use the fact  thar the coordinates of p and Q satisfy the equation y=mx+c to  show that the gradient of PQ is m for all positions of Q.


ok..

Same logic...
m=tan theta
P=(p,q)
Q=(r,s)

tan theta= s-q / r-p
For any value of (r,s) on y=mx+c, (tan theta) will be constant, hence m will be constant

astarmathsandphysics:
Maybe they meant to start from pre first principles ie the principle before the principle

nid404:

--- Quote from: astarmathsandphysics on September 25, 2009, 09:46:22 am ---Maybe they meant to start from pre first principles ie the principle before the principle

--- End quote ---

didn't get that ???

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