Qualification > Math

maths help!!

(1/6) > >>

mousa:
hey everyone , well i got stuck on those questions , astar, nid.. anybody..
help me out!..plz i need workin out with reasoning..

1, let p,with coorinates (p,q), be a fixed point on the 'curve ' with equation y=mx+c and let Q with coordinates (r,s), be any other point on y=mx+c . use the fact  thar the coordinates of p and Q satisfy the equation y=mx+c to  show that the gradient of PQ is m for all positions of Q.

2 there are some values of  a, b and c for which the equation ax+by+c=0 does not represent a straight line. give an example of such values


3 two lines have equations  y=m1x+c1 and y=m2x+c2 and m1m2=-1. prove that the lines are perpendicular.


Thanks in advance..

nid404:
Will answer his tom definitely....have an exam tom..so sorry...tom for sure

astarmathsandphysics:
I answered these questions somewhere else. m1m2=-1 is the def of perpendicular.

Ghost Of Highbury:
the answer for the third one is dere in the question itself..

if m1*m2 = -1

the lines are perpendicular...

slvri:

--- Quote from: eddie_adi619 on September 25, 2009, 06:08:22 am ---the answer for the third one is dere in the question itself..

if m1*m2 = -1

the lines are perpendicular...

--- End quote ---
nope the answer aint in the question...........we did this q in schl a few days ago.....the teacher gave us a weird sort of proof....ill post it when i find it :)

Navigation

[0] Message Index

[#] Next page