Author Topic: chem question  (Read 9590 times)

Offline Ghost Of Highbury

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Re: chem question
« Reply #15 on: September 15, 2009, 02:08:05 pm »
By the way adi,

the EF is C3H6O

for the total mass, shouldnt we add up 3 carbons and 6 hydrogens etc. ?  :-\

(is that what nid and u decided on just now? :P)


yah yah
my bad

tks nid
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nid404

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Re: chem question
« Reply #16 on: September 15, 2009, 02:08:47 pm »
yup that's what i did
12x3=36
+ 6x1=6
+16x1=16
Total=58


Q80BOY

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Re: chem question
« Reply #17 on: September 15, 2009, 02:15:58 pm »
Thanks guys !!

nid404

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Re: chem question
« Reply #18 on: September 15, 2009, 02:17:18 pm »
anytime m8 :)

Q80BOY

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Re: chem question
« Reply #19 on: September 16, 2009, 01:11:15 pm »
hey guys, i have another question ..

Find the Empeical Formula of the following oxide of lead.

It contains 9.7g of lead to every 1g of oxygen

(RAM values .. Pb= 207, O= 16)

the answer is Pb3O4

i dunno what to do after we divide by the smallest answer =/

please help :)
« Last Edit: September 16, 2009, 01:29:03 pm by Q80BOY »

Offline Ghost Of Highbury

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Re: chem question
« Reply #20 on: September 16, 2009, 01:23:58 pm »
hey guys, i have another question ..

Find the Empeical Formula of the following oxide of lead.

It contains 9.7g of lead to every 1g of oxygen

(RAM values .. Pb= 207, O= 16)

the answer is Pb3O3

i dunno what to do after we divide by the smallest answer =/

please help :)

ok.somehow..i find this q wierd,.,

           Pb              O

          9.7              1
          207             16

         0.04686      0.0625

             1             1.33

       
   u get it as PbO1.33 ===> PbO (app.)

is the mass of the oxide given...are the values correct?
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Q80BOY

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Re: chem question
« Reply #21 on: September 16, 2009, 01:28:39 pm »
ya adi .. everything is correct ..

and nothing else is given .. ill have to talk to my teach tomorow cause thats what i got too ..

thanks for the help mate !! :)

Offline Ghost Of Highbury

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Re: chem question
« Reply #22 on: September 16, 2009, 01:45:14 pm »
ya adi .. everything is correct ..

and nothing else is given .. ill have to talk to my teach tomorow cause thats what i got too ..

thanks for the help mate !! :)

maybe nid wud be able to solve this.,..
divine intervention!

Q80BOY

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Re: chem question
« Reply #23 on: September 16, 2009, 01:55:13 pm »
maybe nid wud be able to solve this.,..

i sent her a pm .. maybe she can solve this chemical mystery :P

nid404

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Re: chem question
« Reply #24 on: September 16, 2009, 01:59:15 pm »
I googled it
Single crystals of ?-PbO2 are formed when an intermediate oxide of lead represented by the generic formula, PbOx wherein x denotes a value falling in the range of 1.4 to 1.7, is heated in an aqueous alkali hydroxide solution under a pressure exerted by use of oxygen or an oxygen-containing gas. The single crystals are in the shape of slender rods, have a black color and have a metallic gloss.

and
he mechanochemical processes, including mechanochemical synthesis of mixed-valence lead oxides, in mixtures of PbO, Pb3O4, and PbO2were studied by x-ray diffraction. The results demonstrate that the reduction of Pb4+is accompanied by the formation of Pb2O3, Pb3O4, and possibly PbO1.37. Phases of variable composition close in structure to minium, Pb3O4, are shown to coexist during mechanical processing. The structure of the metastable oxide Pb3O4 – x with Pb2+: Pb4+> 2 (@O4 – 2x ) is tentatively determined. The sequence of the observed transformations is interpreted in terms of the model for the reaction zone, with consideration for primary and secondary interactions.


But I can't really figure it out..... confirm with your teacher

Q80BOY

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Re: chem question
« Reply #25 on: September 16, 2009, 02:04:09 pm »
ya i think i will ..

thanks for the help nid !! :)

nid404

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Re: chem question
« Reply #26 on: September 16, 2009, 02:05:58 pm »
anytime q80

Actually I understood the formation thingy but I can't relate to the empirical formula :(

Offline Ghost Of Highbury

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Re: chem question
« Reply #27 on: September 16, 2009, 02:08:11 pm »
anytime q80

Actually I understood the formation thingy but I can't relate to the empirical formula :(

i got a wierd answer

scroll up
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nid404

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Re: chem question
« Reply #28 on: September 16, 2009, 02:23:18 pm »
saw that...but that is related to the formation somehow....can't figure out how

Offline slvri

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Re: chem question
« Reply #29 on: September 16, 2009, 04:18:49 pm »
1-1.33
multiply by 3
3-4
formula is Pb3O4
i hate A level...........