This is my original solution hpe u understand it.
i think u may
find it in attachment
OKK..FIRST OF ALL
I DIDNT GET Y U APPLIED RATIO PROPORTION WITH 168:9.3::18:x
y 18?
they have talked abt CO2 not H2O
ok..heres the sol.--------------------------
take only NAHCO3 and CO2 into consideration
168g NAHCO3 - 44g CO2 (by molar masseS)
this means that pure NAHCO3 168g will give out 44g of CO2
however here..2.24g of CO2 is given out ..
by ratio and proportion find out how much grams of NAHCO3 should be used to give out 2.24g of CO2
44g - 168g
2.24 - 8.55g
but...here 9.3g of NAHCO3 impure is used
this means that there is 9.3 - 8.55g of impurity = 0.75g of impurity
they've asked to calculate % purity
so what v do is
=> 8.55/9.3 * 100 = 92%