Qualification > Sciences
Chemistry...
slvri:
--- Quote from: eddie_adi619 on September 07, 2009, 04:49:37 pm ---
--- Quote from: slvri on September 07, 2009, 04:34:12 pm ---
--- Quote from: nid404 on September 07, 2009, 04:17:58 pm ---
ok so
40g H and 20g O
WHat you first do is find out % composition of each
so
H O
% composition 40/60*100 20/60*100
ratio of compostion 2 : 1
It's H2O
That's how you do empirical formula for this one i guess
--- End quote ---
but hows that possible???? i mean u found percentage composition by mass but thats not necessarily the same as the empirical formula(number of moles of atoms of each element)
--- End quote ---
true..
u didnt divide it by the molar mass
--- End quote ---
and anyways hydrogen atoms are so much lighter than oxygen atoms that the mass of hydrogen must be less than that of oxygen e.g. 4g of hydogen combines with 32g of oxygen to produce 36g of water
Ghost Of Highbury:
--- Quote from: slvri on September 07, 2009, 04:54:18 pm ---
--- Quote from: eddie_adi619 on September 07, 2009, 04:49:37 pm ---
--- Quote from: slvri on September 07, 2009, 04:34:12 pm ---
--- Quote from: nid404 on September 07, 2009, 04:17:58 pm ---
ok so
40g H and 20g O
WHat you first do is find out % composition of each
so
H O
% composition 40/60*100 20/60*100
ratio of compostion 2 : 1
It's H2O
That's how you do empirical formula for this one i guess
--- End quote ---
but hows that possible???? i mean u found percentage composition by mass but thats not necessarily the same as the empirical formula(number of moles of atoms of each element)
--- End quote ---
true..
u didnt divide it by the molar mass
--- End quote ---
and anyways hydrogen atoms are so much lighter than oxygen atoms that the mass of hydrogen must be less than that of oxygen e.g. 4g of hydogen combines with 32g of oxygen to produce 36g of water
--- End quote ---
very true///
nid404:
--- Quote from: slvri on September 07, 2009, 04:54:18 pm ---
--- Quote from: eddie_adi619 on September 07, 2009, 04:49:37 pm ---
--- Quote from: slvri on September 07, 2009, 04:34:12 pm ---
--- Quote from: nid404 on September 07, 2009, 04:17:58 pm ---
ok so
40g H and 20g O
WHat you first do is find out % composition of each
so
H O
% composition 40/60*100 20/60*100
ratio of compostion 2 : 1
It's H2O
That's how you do empirical formula for this one i guess
--- End quote ---
but hows that possible???? i mean u found percentage composition by mass but thats not necessarily the same as the empirical formula(number of moles of atoms of each element)
--- End quote ---
true..
u didnt divide it by the molar mass
--- End quote ---
and anyways hydrogen atoms are so much lighter than oxygen atoms that the mass of hydrogen must be less than that of oxygen e.g. 4g of hydogen combines with 32g of oxygen to produce 36g of water
--- End quote ---
I know...i just tried to derive the empirical formula...found it this way so put it up :P..I know this is theoritically incorrect....but i just gave it a try
@shreyapril-plz check the q again...im being screwed for trying some crazy method
Ghost Of Highbury:
hahaha
nice one though.
lolzz
nid404:
--- Quote from: eddie_adi619 on September 08, 2009, 07:06:03 am ---hahaha
nice one though.
lolzz
--- End quote ---
very innovative no?? :P
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