Qualification > Sciences
Chemistry...
slvri:
--- Quote from: eddie_adi619 on September 07, 2009, 10:47:02 am ---wat answer r u getting..slvri?
--- End quote ---
same as the one ur getting.........definitely some problem in da question
nid404:
ok so
40g H and 20g O
WHat you first do is find out % composition of each
so
H O
% composition 40/60*100 20/60*100
ratio of compostion 2 : 1
It's H2O
That's how you do empirical formula for this one i guess
Ghost Of Highbury:
dont u do it by the mass method...???
can u plz spot the error in the steps i rote...
slvri:
--- Quote from: nid404 on September 07, 2009, 04:17:58 pm ---
ok so
40g H and 20g O
WHat you first do is find out % composition of each
so
H O
% composition 40/60*100 20/60*100
ratio of compostion 2 : 1
It's H2O
That's how you do empirical formula for this one i guess
--- End quote ---
but hows that possible???? i mean u found percentage composition by mass but thats not necessarily the same as the empirical formula(number of moles of atoms of each element)
Ghost Of Highbury:
--- Quote from: slvri on September 07, 2009, 04:34:12 pm ---
--- Quote from: nid404 on September 07, 2009, 04:17:58 pm ---
ok so
40g H and 20g O
WHat you first do is find out % composition of each
so
H O
% composition 40/60*100 20/60*100
ratio of compostion 2 : 1
It's H2O
That's how you do empirical formula for this one i guess
--- End quote ---
but hows that possible???? i mean u found percentage composition by mass but thats not necessarily the same as the empirical formula(number of moles of atoms of each element)
--- End quote ---
true..
u didnt divide it by the molar mass
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