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ohh..tksbut in the first one i explained pereviouslythe sulphur gains oxygen atoms and its oxidation state also increases..this proves that it is oxidationbut...in the second equation the sulphur's oxidation state doesn't change...
S has many oxidation states including -2,0,2,4,6...in this particular reaction the oxidation state of S is "+2"a decrease in oxidation state - reduction an increase in oxidation state - oxidation1.) S + O2 -> SO2 here at the left handside, as sulphur exists itself (not compound), the oxidation state is 0 at the right hand sidde it forms a compound and gains an oxidation state of +2 = this is oxidation whereas O has an oxidation state of "0" in the left hand side and decreases to -4 in the right hand side this is reduction therefore its redox
in question 38 june 08......
Quote from: Bani on June 11, 2009, 06:00:38 pmQuote from: sweetest angel on June 11, 2009, 05:51:43 pmQuote from: Bani on June 11, 2009, 05:47:16 pmthanks a lot everyone!someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?since in equation 3 no reactants have lost or gained electrons, oxygen or hydrogen!Ya,but why is equation 1 and 2 REDOX?1 and 2 are only oxidation, not reduction...please help...it's a little difficult to explainbut i'll try...in the first one Sulphur gains oxygen atoms(oxidation) but oxygen gains electrons(reduction).in the second one sulphur gains oxygen but oxygen gains electronswhereas in third one although oxygen is gained, there is no transfer of electrons and hydrogen does not lose oxygen but combines with SO4It's very difficult to explain. * Oxygen's oxidation state reduces in the covalent bond it forms with sulphur
Quote from: sweetest angel on June 11, 2009, 05:51:43 pmQuote from: Bani on June 11, 2009, 05:47:16 pmthanks a lot everyone!someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?since in equation 3 no reactants have lost or gained electrons, oxygen or hydrogen!Ya,but why is equation 1 and 2 REDOX?1 and 2 are only oxidation, not reduction...please help...
Quote from: Bani on June 11, 2009, 05:47:16 pmthanks a lot everyone!someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?since in equation 3 no reactants have lost or gained electrons, oxygen or hydrogen!
thanks a lot everyone!someone please try answering my previous question (M/J 2007, Q16-----the one about redox reaction) Why is the answer C?
Can u please tell me whats the answer for May/June 2008 Question 19Mark scheme says D.. i think its C Cause 2KOH --> H20 thats ph going from 14 - 7 so decreases :s why is it d in the ms its wrong rite?
can u explain further ... and please are u 100%?
Quote from: Petrol on June 11, 2009, 07:11:09 pmcan u explain further ... and please are u 100%?yes im 100% sure. See when the two react, KOH is in excess..it still remains in the solution after the reaction is over. The pH of the solution increases as the alkali is in excess. I've tried my best to explain it.
Could someone help me with question 20 in november 2008. I don't understand y ph should increase...
