Physics Discussion HERE ONLY!

[MR.BooMBastiC]

i wrote da same!!!!!!!!!

i knew others but i didnt knew how to use them!!

[thukon]

I wrote micrometer screw gauge.
The refracted angle is 50 sumthing. All u ppl used the formula R.I.=sin i / sin r, but the thing you didnt realize was that the medium outside was air, so you actually have to substitute the r value.

[MR.BooMBastiC]

I wrote micrometer screw gauge.
The refracted angle is 50 sumthing. All u ppl used the formula R.I.=sin i / sin r, but the thing you didnt realize was that the medium outside was air, so you actually have to substitute the r value.

yeah!!

well that is known as the {{principle of reversebility of light}}

[MaNa]

i wrote a ruller too bcuz i similer question was there in paper 6
where they asked u the hight of the paper n then they ashked height of one
its i guess paper 6 06 so i remembered n i wrote it with correct methord
ii am not sure for the didode i wrote D n the i set the corrent form right to left :S
ad for the force thingi in newton i made a trianle not  parellogram iam soo depressed:'(

[annie_angel]

Why would you divide refractive index by one?? I did
R.I = sin i/sin r ...
1.49 = sin 35 / sin r
and my answer was 23. something

it waz 25...not 35

[MaNa]

Why would you divide refractive index by one?? I did
R.I = sin i/sin r ...
1.49 = sin 35 / sin r
and my answer was 23. something

it waz 25...not 35

i dont know what i worte i have complete forgotten
but i remember it was in 20ss
5alas lets pray the threshold for this paper is loow low lowww!!!:D

[annie_angel]

Why would you divide refractive index by one?? I did
R.I = sin i/sin r ...
1.49 = sin 35 / sin r
and my answer was 23. something

it waz 25...not 35

i dont know what i worte i have complete forgotten
but i remember it was in 20ss
5alas lets pray the threshold for this paper is loow low lowww!!!:D

Inshaallah Inshaallah it will be!!

[MR.BooMBastiC]

IT WAS 58.7 THE REFACTED RAY
IT CANNOT BE IN 28
CUZ THE INCIDENT RAY WAS 35

[MaNa]

IT WAS 58.7 THE REFACTED RAY
IT CANNOT BE IN 28
CUZ THE INCIDENT RAY WAS 35

tch i dont remember
ok w8 the critical angle was 90-35

[MR.BooMBastiC]

CRITICAL ANGLE WAS 42 I CHECKED IT WITH DA PROTRACTOR

[MaNa]

CRITICAL ANGLE WAS 42 I CHECKED IT WITH DA PROTRACTOR

UGH I HOPE MY PEN HAD A MAGIC INK
which can change all the answer to corect
i really hope the threshold isss doowwwwn
Inshllah InshAllah Inshallah:D

[IGCSE nightmare]

The fraction question .. I got 1\2! I first wrote it as 1\8 but then I recognized that wind becomes slower when it is heavier.
But that makes sense if the speed is half less then the mass is then more which makes the output half less. [ Blowing slower , less output ]

[omar777]

guys just by looking at the ray you can see it is bending away the from the normal... its impossible that the answer is in the '20s' it was 58 point something
and i think the critical angle was a bit more than 42 because when the incident ray was 42, the refracted ray was a bit less than 90... so i wrote 43

[annie_angel]

i rote 90 cuz whn da incident ray goes in tht way...td c-angle goes 90

[MR.BooMBastiC]

CRITICAL ANGLE.......CAN NEVER BE 90