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Author Topic: Additional Math Help HERE ONLY...!  (Read 76006 times)

Offline J.Darren

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Re: Additional Math Help HERE ONLY...!
« Reply #420 on: June 09, 2010, 04:48:52 pm »
Quote from: BlackBunny103 on June 09, 2010, 04:46:59 pm
I dearly pray to GOD, though I'm Buddhist, that relative vel wouldn't come up. I HATE IT >:(
LOL I am hoping for Relative Velocity ... Aliens colliding with each other on a screen, how exciting :P
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Offline adrian1993

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Re: Additional Math Help HERE ONLY...!
« Reply #421 on: June 09, 2010, 04:49:51 pm »
Apparently they asked the centre to provide a graph paper for the second paper as well. Area under curve then appeared in the optional section. Maybe this time they'll put it in the compulsory parts.
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Offline J.Darren

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Re: Additional Math Help HERE ONLY...!
« Reply #422 on: June 09, 2010, 04:51:22 pm »
Quote from: adrian1993 on June 09, 2010, 04:49:51 pm
Apparently they asked the centre to provide a graph paper for the second paper as well. Area under curve then appeared in the optional section. Maybe this time they'll put it in the compulsory parts.
Oh right ... That's depressing, I hate drawing graphs D: The sketch that I did for the two cos x graphs were douggy ... But at least I have managed to obtain 4 solutions so whatever ... What did you guys got for the log Q By the way ?
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Offline adrian1993

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Re: Additional Math Help HERE ONLY...!
« Reply #423 on: June 09, 2010, 04:54:19 pm »
log Q? Enlighten me as I have no memory of such a question.

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Offline jellybeans

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Re: Additional Math Help HERE ONLY...!
« Reply #424 on: June 09, 2010, 04:54:57 pm »
Quote from: J.Darren on June 09, 2010, 04:51:22 pm
Oh right ... That's depressing, I hate drawing graphs D: The sketch that I did for the two cos x graphs were douggy ... But at least I have managed to obtain 4 solutions so whatever ... What did you guys got for the log Q By the way ?

sth like 30.8 . :P and you? for Q
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Offline J.Darren

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Re: Additional Math Help HERE ONLY...!
« Reply #425 on: June 09, 2010, 04:57:26 pm »
Quote from: jellybeans on June 09, 2010, 04:54:57 pm
sth like 30.8 . :P and you? for Q
naa Q - Question ... I got 2.2 something for log p ...
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Offline jellybeans

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Re: Additional Math Help HERE ONLY...!
« Reply #426 on: June 09, 2010, 04:58:39 pm »
Quote from: J.Darren on June 09, 2010, 04:57:26 pm
naa Q - Question ... I got 2.2 something for log p ...

didnt they ask for Q when V = blahblah?
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Offline J.Darren

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Re: Additional Math Help HERE ONLY...!
« Reply #427 on: June 09, 2010, 04:59:14 pm »
Quote from: jellybeans on June 09, 2010, 04:58:39 pm
didnt they ask for Q when V = blahblah?
I thought it is when v = something, q = unknown ?
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Offline Dibss

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Re: Additional Math Help HERE ONLY...!
« Reply #428 on: June 09, 2010, 05:03:52 pm »
In variant 2 did you guys have to DRAW any graphs?
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Offline J.Darren

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Re: Additional Math Help HERE ONLY...!
« Reply #429 on: June 09, 2010, 05:04:18 pm »
Quote from: Dibss on June 09, 2010, 05:03:52 pm
In variant 2 did you guys have to DRAW any graphs?
Two graphs in total - log x and cos x.
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Offline jellybeans

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Re: Additional Math Help HERE ONLY...!
« Reply #430 on: June 09, 2010, 05:05:36 pm »
Quote from: J.Darren on June 09, 2010, 04:59:14 pm
I thought it is when v = something, q = unknown ?

hahaha i found logq and then q .. :P :)
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Offline adrian1993

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Re: Additional Math Help HERE ONLY...!
« Reply #431 on: June 09, 2010, 05:05:44 pm »
Oh that question. They asked for log p when v=170.

The answer is 0.833 or 5/6

Can someone please enlighten me to the below question:-

g(x)-->1-(x^2)+6x
domain is 2<=x<=7

Find range.

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Offline Dibss

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Re: Additional Math Help HERE ONLY...!
« Reply #432 on: June 09, 2010, 05:08:25 pm »
Quote from: J.Darren on June 09, 2010, 05:04:18 pm
Two graphs in total - log x and cos x.
We didn't even need graph paper for V1 so I'm assuming we'll have to draw tomorrow... Eeeek :|
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Offline J.Darren

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Re: Additional Math Help HERE ONLY...!
« Reply #433 on: June 09, 2010, 05:09:43 pm »
Quote from: adrian1993 on June 09, 2010, 05:05:44 pm
Oh that question. They asked for log p when v=170.

The answer is 0.833 or 5/6

Can someone please enlighten me to the below question:-

g(x)-->1-(x^2)+6x
domain is 2<=x<=7

Find range.


I thought the question required us to find the exact value of p instead of log p ?
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Offline adrian1993

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Re: Additional Math Help HERE ONLY...!
« Reply #434 on: June 09, 2010, 05:10:08 pm »
Hey dibbs, what came out for V1?

Darren, nope. It says log p when V=170.
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