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Additional Math Help HERE ONLY...!

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astarmathsandphysics:

--- Quote from: shan2391 on June 02, 2009, 03:24:59 pm ---HOW do u get y
   3^2y +5(3^y-10)=0

--- End quote ---

sub p=3^y to get p2+5(p-10)=0 so p2+5p-50=(p+10)(p-5)=0 so p=-10 or 5 so y=(logp)/log3 =(log-10)/log3 impossible since log-10 does not exist or y=(log5)/log3

shan2391:
Thanks astar :)
By the way i was reading the syllabus n did not find velcity n relative velocity in it

sweetsh:
3(sinx-cosx)=2(sinx+cosx)

?

sweetsh:
PLease answer

shan2391:
3sinx-3cosx=2sinx+2cosx
sinx=5cosx
sinx/cosx=5
tanx=5
x=78.69

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