Qualification > Math
Additional Math Help HERE ONLY...!
astarmathsandphysics:
--- Quote from: vanibharutham on June 02, 2009, 03:10:26 pm ---be careful with quadratics,
the range only go down to the minimum or up to maximum point
with straight line graphs you can subsitite values
however, with quadratics or cubes or absolute values, you need to basically find that turning point within your given domain
--- End quote ---
No you complete the square egy=x^2+6x-1
=(x+3)^2-3^2-1=(x+3)^2-10 so range is y>=-10
moraesikae:
--- Quote from: astarmathsandphysics on June 02, 2009, 03:13:47 pm ---
--- Quote from: vanibharutham on June 02, 2009, 03:10:26 pm ---be careful with quadratics,
the range only go down to the minimum or up to maximum point
with straight line graphs you can subsitite values
however, with quadratics or cubes or absolute values, you need to basically find that turning point within your given domain
--- End quote ---
No you complete the square egy=x^2+6x-1
=(x+3)^2-3^2-1=(x+3)^2-10 so range is y>=-10
--- End quote ---
so if the domain is given,, e.g -2<x<4??
what would the range be>?
shan2391:
HOW do u get y
3^2y +5(3^y-10)=0
astarmathsandphysics:
--- Quote from: moraesikae on June 02, 2009, 03:16:41 pm ---
--- Quote from: astarmathsandphysics on June 02, 2009, 03:13:47 pm ---
--- Quote from: vanibharutham on June 02, 2009, 03:10:26 pm ---be careful with quadratics,
the range only go down to the minimum or up to maximum point
with straight line graphs you can subsitite values
however, with quadratics or cubes or absolute values, you need to basically find that turning point within your given domain
--- End quote ---
No you complete the square egy=x^2+6x-1
=(x+3)^2-3^2-1=(x+3)^2-10 so range is y>=-10
--- End quote ---
so if the domain is given,, e.g -2<x<4??
what would the range be>?
--- End quote ---
In the example I gave the minimum of the graph was at x=-3. This is included in my domain but not the one you give -2<x<4. In this case you would sub x=-2 and x=4 to get the range. In the case -4<x<4 x=-3 is included so the range woul be from -10 to (4+3)^2-10=39
moraesikae:
--- Quote from: astarmathsandphysics on June 02, 2009, 03:38:01 pm ---
--- Quote from: moraesikae on June 02, 2009, 03:16:41 pm ---
--- Quote from: astarmathsandphysics on June 02, 2009, 03:13:47 pm ---
--- Quote from: vanibharutham on June 02, 2009, 03:10:26 pm ---be careful with quadratics,
the range only go down to the minimum or up to maximum point
with straight line graphs you can subsitite values
however, with quadratics or cubes or absolute values, you need to basically find that turning point within your given domain
--- End quote ---
No you complete the square egy=x^2+6x-1
=(x+3)^2-3^2-1=(x+3)^2-10 so range is y>=-10
--- End quote ---
so if the domain is given,, e.g -2<x<4??
what would the range be>?
--- End quote ---
In the example I gave the minimum of the graph was at x=-3. This is included in my domain but not the one you give -2<x<4. In this case you would sub x=-2 and x=4 to get the range. In the case -4<x<4 x=-3 is included so the range woul be from -10 to (4+3)^2-10=39
--- End quote ---
o rightttt!!! thx v much!!!!!!!
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