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Author Topic: Physics nov 08  (Read 2375 times)

Offline a7medokool

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Physics nov 08
« on: May 24, 2009, 03:58:04 pm »
Hello could any 1 tell me how to do Q 1 c and D on this physics paper
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Offline Shogun

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Re: Physics nov 08
« Reply #1 on: May 24, 2009, 04:07:04 pm »
hi, is this paper 3 or 6?
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Offline a7medokool

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Re: Physics nov 08
« Reply #2 on: May 24, 2009, 04:11:09 pm »
yea yea sry didnt mention the paper its Paper 3
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Offline Shogun

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Re: Physics nov 08
« Reply #3 on: May 24, 2009, 04:14:12 pm »
the one about friction with 14 newton force right?
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Offline a7medokool

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Re: Physics nov 08
« Reply #4 on: May 24, 2009, 04:17:12 pm »
hmmm yea and could u help me to 1B too how to calcluate the mass of the trolley
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Offline Shogun

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Re: Physics nov 08
« Reply #5 on: May 24, 2009, 04:19:11 pm »
alright
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Offline a7medokool

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Re: Physics nov 08
« Reply #6 on: May 24, 2009, 04:25:50 pm »
So shogun did u figuire it out yet?
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Offline Shogun

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Re: Physics nov 08
« Reply #7 on: May 24, 2009, 04:36:35 pm »
bii)the equation is:
force=mass* acceleration

biii) f=ma
where f=force
          m=mass
         a=acceleration
so here a=2 and 'm' is giben as 12kg

so to find resultant force (f): 12*2=24N

ci)to find the total resultant force u have to add 24N and 14N (given in the question) we need to find 'a' (acceleration)
so 24+14=38N(total resultant force)
then use the formula (f=ma)
so it would be 38N=12*a
then by changing position (algebra) it will become 38/12
u get aceeleration 'a'= 3.17 meter per second square (m/s^2)

ci) use the formula to find velocity which is (velocity = acceleration*time) where 'a'=3.17 (from previous answer) and 't'=2.5s (given in the question)
so then 3.17*2.5
u get= 7.9m/s

d) the car moves with uniform acceleration. ((because at original angle of incline. it didnt accelerate because no resultant as friction force was same as the acceleration of the car.but here lubrication was added so friction froce was reduced and there was a resultant force (the accleration) thus the car aceelerated.))

any confusion or difficulty plz do ask me, im all here





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Offline a7medokool

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Re: Physics nov 08
« Reply #8 on: May 24, 2009, 06:03:38 pm »
Hmmm this is the 2nd variant Questions? right
I was aking about the 1st
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Offline Shogun

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Re: Physics nov 08
« Reply #9 on: May 24, 2009, 06:09:58 pm »
oh ok
then i ll try to find out the first variant one..
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Offline a7medokool

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Re: Physics nov 08
« Reply #10 on: May 24, 2009, 06:11:57 pm »
Its in the site Both variants are there
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Offline zubair_slipknot

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Re: Physics nov 08
« Reply #11 on: May 24, 2009, 06:14:02 pm »
hey if u can post the question its excelllent...if its too long its ok i am trying to download the 2st varient past paper
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Offline Shogun

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Re: Physics nov 08
« Reply #12 on: May 24, 2009, 07:36:01 pm »
umm getting it sorry cuz the downlad took time
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Offline Ghost Of Highbury

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Re: Physics nov 08
« Reply #13 on: May 24, 2009, 07:41:33 pm »
k.. heres ur answer..

1 c.)  use the formula F = m *a....therefore 0.7 = 0.8 (mass of trolley) * a

=> a = 0.7/0.8 = 0.875

d.) 1.) use the formuala v = u + at
u = 0, v = at
look at the table the acceleration of the trolley is 0.5 when the weight is 0.4
therefore v = 0.5 * 1.2 = 0.6 m/s

d. 2.) use the formula s = ut + 1/2 at(2)
u = 0
therefore s = 1/2 at(2)
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hope it helped u ...!! :)
                 
                = 0.5 * 0.5 * 1.2 *1.2 = 0.36 m

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Offline tmisterr

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Re: Physics nov 08
« Reply #14 on: May 24, 2009, 07:42:28 pm »
how do u do question 2(d) on the nov 2008 paper 3? on any variant, doesn't matter...
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