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Dramien:
hey got some notes which hav all formulae etc for revsion.. hope ull like it...

Ghost Of Highbury:

--- Quote from: Guthixol on June 03, 2009, 04:12:00 pm ---may someone answer this question
paper 3 oct/nov 2008 q (2) all please and :D thank you

--- End quote ---

heres how u do it
a) find it attached
b) if the masses are in equilibrium and there is no net moment, the disc will not move toward any side
c) (200/100)N * 4m = 8Nm
   (100/100)N  *   8m = 8Nm
moment due to first mass = 8Nm
moment due to second mass = 8Nm

d) total mass acting = 100g + 200g + 200g (of the disc) = 500g = 5N

Shogun:
2a) put different value of masses on bothe sides of the pivot  but make sure tht after using the formula (fxd) (where
f=force and d=distance) the product must be same. (then only they are balanced i.e in equilibrium)

 the distance are given for each hole to the pivot. so i recomend to take the first hole(with distance 4cm) and add mass 200g at one side of the pivot. and on the other side,  add mass 100g on the second hole (with disatnce 8 cm from teh pivot)

but first convert the masses to forces by multiplying the mass into 10, so 200( convert this to killogram by deviding it by 1000 ) 0.2 x 10 u get 2
so when using the formula "fxd " u get on one side: 2x4=8Nm
                                                     and                                      
                                                   on the other side: 1x8=8Nm
                         - see both have the same product so it is now they are balanced(in equilibrium)


ans2b) the disc does not move or rotate as u put the mass so they are balanced so no turning effect which means no moment.

c)use formula "fxd" but convert the mass in to force but multiplying them in to 10 and convert the mass to kg first
               2x4=8Nm
               1x8=8Nm

d)this is the force of pivot which is downwar to get tht simply add the masses u put
1+8=9N

but rmember u can choose any mass at any distance but the product with equation "fxd" must be same

thts all,hope this helped, any confusion or difficulties or help u need, im all here

Eamyzz:

--- Quote from: Guthixol on June 03, 2009, 04:12:00 pm ---may someone answer this question
paper 3 oct/nov 2008 q (2) all please and :D thank you

--- End quote ---


thats easy


look first
a)
u no that moment=force * distance
so 4 instance i chose 200g and 100g
to make sure they both have da same moment
200*4=100*8
800=800
so that its at equilibrium

b)
It will stay stable which ensures that its at equilibrium.

c)
do the same thing i used to explain part a)
M1=200*10*4(*10 because its force and 200g is mass so *10 to make it weight)
m2=100*10*8

M1=M2
8000Nm=8000Nm
and the answer 4 da 2 blaks is 8000 or wateva accordind to ur chosen values

d) (200*10)+(100*10)+(200*10)

=5000N
i multiplies each one by 10 to make them forces



hope it helped :)

Shogun:
oh wait forgot to add 2 cuz 200g of the disc (covert to killo then to force) . in my last answer

so its 1+2+2=5N

i added wrong mass silly me..

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