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Author Topic: Chemistry Help HERE ONLY !!  (Read 107374 times)

Offline ig_kid

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Re: Chemistry Help HERE ONLY !!
« Reply #630 on: May 31, 2009, 12:58:40 pm »
i know.....same problem here.
u could just open the question paper from free exam papers and forget about the one u solved, that's wat i did.
Gd luck everybody.....u'll need it ;)
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Offline emi

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Re: Chemistry Help HERE ONLY !!
« Reply #631 on: May 31, 2009, 01:04:01 pm »
WTH!!!    my Question paper is tottaly different  though its same year and everything ,, i will try to scan the first page van u guys tell me which year it is .
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Offline SGVaibhav

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Re: Chemistry Help HERE ONLY !!
« Reply #632 on: May 31, 2009, 01:07:12 pm »
many ppl know abuot this
GodFather93, Q80Boy also know about it.
it might be a specimen or something
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Offline ig_kid

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Re: Chemistry Help HERE ONLY !!
« Reply #633 on: May 31, 2009, 01:09:23 pm »
I hv the same problem and i think it is a very old pass paper without a mark scheme cuz i searched for it on all the years but couldn't find it. >:(
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Offline emi

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Re: Chemistry Help HERE ONLY !!
« Reply #634 on: May 31, 2009, 01:11:20 pm »
sry scanner is dead, i took some pics by mobile though its not clear
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nid404

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Re: Chemistry Help HERE ONLY !!
« Reply #635 on: May 31, 2009, 02:32:03 pm »
Quote from: amy.mym on May 31, 2009, 01:41:01 pm
Guys how do we do Question " 7 a) i) " on Paper 3 November 2008

The volumes one

can someone give me the steps as well
[/b][/color]

the volume ratio is 1:6.5
since butane is 10cm3 oxygen should be 10x6.5= 65cm3
but since it is 100cm3 there is 35cm3excess oxygen
volume of carbon dioxide is 4 times the volume of butane(ratio 1:4) so it is 10x4=40cm3
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Offline MaNa

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Re: Chemistry Help HERE ONLY !!
« Reply #636 on: May 31, 2009, 02:34:07 pm »
Quote from: amy.mym on May 31, 2009, 01:41:01 pm
Guys how do we do Question " 7 a) i) " on Paper 3 November 2008

The volumes one

can someone give me the steps as well
[/b][/color]
ok is it 1st varient or seocnd varient
ill tell u 1st
the ratio is
1 mole of oxgen:6.5 moles of oxygen
10cm3                     ?
therefore
6.5*10
=65
so 100-65=35chm3
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Offline MaNa

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Re: Chemistry Help HERE ONLY !!
« Reply #637 on: May 31, 2009, 02:36:10 pm »
n for co2
 ratio again
1:4
so in 10cm3 how much co2 would be formed
4*10=40cm3
hopes that helps:)
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Offline cactus_360

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Re: Chemistry Help HERE ONLY !!
« Reply #638 on: May 31, 2009, 02:43:27 pm »
is this da 1st varient or da 2nd if its 2nd then ur ans is wrong ,manah
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Offline MaNa

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Re: Chemistry Help HERE ONLY !!
« Reply #639 on: May 31, 2009, 02:45:34 pm »
Quote from: cactus_360 on May 31, 2009, 02:43:27 pm
is this da 1st varient or da 2nd if its 2nd then ur ans is wrong ,manah
its 1st vareint
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Offline cactus_360

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Re: Chemistry Help HERE ONLY !!
« Reply #640 on: May 31, 2009, 02:47:44 pm »
then its ok....................so finally ur 400th post
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Offline Clem

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Re: Chemistry Help HERE ONLY !!
« Reply #641 on: May 31, 2009, 02:51:04 pm »
Hey! Can anyone help me with question 6cii november 03 p3 ??
Thank youu
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nid404

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Re: Chemistry Help HERE ONLY !!
« Reply #642 on: May 31, 2009, 02:56:07 pm »
Quote from: Clem on May 31, 2009, 02:51:04 pm
Hey! Can anyone help me with question 6cii november 03 p3 ??
Thank youu

There's no q.6 in nov 2003.

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Offline Clem

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Re: Chemistry Help HERE ONLY !!
« Reply #643 on: May 31, 2009, 03:05:45 pm »
Ummm....
Question 6 c ii : Suggest an explanation why butan-1-ol cannot form long polymer molecules but ethane-1,2 diol can.
My friend told me it's because it has only one OH group, but so do amino acids and they still polymerize anyway.
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Offline fear_fear

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Re: Chemistry Help HERE ONLY !!
« Reply #644 on: May 31, 2009, 03:09:26 pm »
I have a moles question, if i want to find the number of moles of Chlorine cl2.

I apply this formula: mass(g)/Atomic No.

eg. 35.5g/35.5 = 1 mole but since it is cl2 do i multiply the 1 mole by 2 or not

basically what i'm trying to say is does Cl2 mean that i have 2 moles of Chlorine?
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