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Chemistry Help HERE ONLY !!
nid404:
--- Quote from: amy.mym on May 31, 2009, 01:41:01 pm ---Guys how do we do Question " 7 a) i) " on Paper 3 November 2008
The volumes one
can someone give me the steps as well[/b][/color]
--- End quote ---
the volume ratio is 1:6.5
since butane is 10cm3 oxygen should be 10x6.5= 65cm3
but since it is 100cm3 there is 35cm3excess oxygen
volume of carbon dioxide is 4 times the volume of butane(ratio 1:4) so it is 10x4=40cm3
MaNa:
--- Quote from: amy.mym on May 31, 2009, 01:41:01 pm ---Guys how do we do Question " 7 a) i) " on Paper 3 November 2008
The volumes one
can someone give me the steps as well[/b][/color]
--- End quote ---
ok is it 1st varient or seocnd varient
ill tell u 1st
the ratio is
1 mole of oxgen:6.5 moles of oxygen
10cm3 ?
therefore
6.5*10
=65
so 100-65=35chm3
MaNa:
n for co2
ratio again
1:4
so in 10cm3 how much co2 would be formed
4*10=40cm3
hopes that helps:)
cactus_360:
is this da 1st varient or da 2nd if its 2nd then ur ans is wrong ,manah
MaNa:
--- Quote from: cactus_360 on May 31, 2009, 02:43:27 pm ---is this da 1st varient or da 2nd if its 2nd then ur ans is wrong ,manah
--- End quote ---
its 1st vareint
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