an observer at the top of a tower of height 20m sees a man due east if him at an angle of depression of 27 degree . He sees another man due south oh him at an angel of depression of 30 degree. find the distance between the two men on the ground .
this is an Question in the trigonometry can you tell me how to solve it ?? at MS the answer is 52.4 .
thanks
Horizontal distance from tower to 1st man: tan27=o/a=20/a so a=20/tan27=39.25
Horixontal distance from tower to 2nd man=20/tan30=34.64
There is a right angle between these 2 lengths so use Pythagoras theorem
d=sqrt(39.25^2+34.64^2)=52.4m