Ok so do u get that Possible arrangement for men = 6!
basically it means the 'position' of men could be:
__M6__M5__M3__M4__M1__M2__
__M5__M1__M2__M4__M3__M6__ and so on .....
So there are 6! positions (permutations) of men in that group..
Then do u get Possible arrangement for women = 7 P 3
Basically there are 7 spaces for W1,W2 or W3. So (say )we put W2 in any 7 spaces...then we put W1 in the remaining 6 spaces (since 1 is already taken up by W2) and then we put W3 in the remaining 5 places....
So there are 7*6*5 = 7 P 3 ways of putting the 3 women in the spaces...
thats why : All together the possible arrangement = 6 ! x 7P3 = 6! x 7 x 6 x 5 = 151 200
This method is effective as it ensures that 2 women don't stand together! In fact if u check the CIE stats 1 book then it has this method in the P and C chapter!!
But is there some other method???