Author Topic: Maths & Physics Help  (Read 17840 times)

Offline nox_fjmoony

  • SF Immigrant
  • **
  • Posts: 85
  • Reputation: 5141
Re: Need help in additional maths.
« Reply #15 on: June 21, 2009, 12:46:20 pm »
hey thanks Astar.
But you see its where the e part that I don't understand. I'm just starting add maths for the october november session and well I really don't understand how to get the e thingy.
And thanks a lot again.
^_^

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Need help in additional maths.
« Reply #16 on: June 21, 2009, 01:05:29 pm »
I edited my post to make it clearer.

To solve the equation y=lognx raise the base to the power of both side so ny=x

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Need help in additional maths.
« Reply #17 on: June 21, 2009, 01:10:40 pm »
ln x is special notation for lognx=lnx

Offline nox_fjmoony

  • SF Immigrant
  • **
  • Posts: 85
  • Reputation: 5141
Re: Need help in additional maths.
« Reply #18 on: June 21, 2009, 03:06:00 pm »
thanks
but
I have a problem in another part
The part where it becomes x=e^1/2 all of a sudden. I'm quite outta practice and so don't quite understand it. Didn't understand that part in the mark scheme either.

Also whats the relationship between ln and e please?
Thankyou very very much Astar. ^_^

Really grateful.
:D

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Need help in additional maths.
« Reply #19 on: June 21, 2009, 03:43:42 pm »
2lnx=1 so lnx=1/2 so e^{lnx}=e^{1/2} so x=e^{1/2}

Offline nox_fjmoony

  • SF Immigrant
  • **
  • Posts: 85
  • Reputation: 5141
Re: Need help in additional maths.
« Reply #20 on: June 21, 2009, 04:52:02 pm »
Ok
Another question
I guess by this time you might've guessed I"m absolutely stupid and a dunce. But I have to know this.
ok so how does lnx=1/2 becomes e^lnx=e^1/2 ?
I don't know this.
what do you do to make it like this?
 
I'm sorry but as you see I don't know much about ln and log and e and stuff.
Ok thanks again.

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Need help in additional maths.
« Reply #21 on: June 21, 2009, 05:53:21 pm »
To eliminate a log you raise the base to the power of both sides. Here the base is e=2.718.........

Offline nox_fjmoony

  • SF Immigrant
  • **
  • Posts: 85
  • Reputation: 5141
Re: Need help in additional maths.
« Reply #22 on: June 22, 2009, 04:10:25 pm »
Ah
Finally
I get it. Thanks so much, wouldn't have known this without you tellin me.
Thanks again.
 ;D

Offline nox_fjmoony

  • SF Immigrant
  • **
  • Posts: 85
  • Reputation: 5141
Re: Need help in additional maths.
« Reply #23 on: June 23, 2009, 01:51:54 pm »
hey astar
Another question. Um how does e^lnx=e^1/2 become x=e^1/2 later on?
ok
thanks

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: Need help in additional maths.
« Reply #24 on: June 23, 2009, 01:54:25 pm »
hey astar
Another question. Um how does e^lnx=e^1/2 become x=e^1/2 later on?
ok
thanks

e^ cancels loge=ln

ln is special notation for loge
« Last Edit: June 23, 2009, 01:58:30 pm by astarmathsandphysics »

nid404

  • Guest
Re: Maths & Physics Help
« Reply #25 on: September 26, 2009, 06:30:50 pm »
Sir, do you notes on your site for complex numbers??

holtadit

  • Guest
Re: Maths & Physics Help
« Reply #26 on: October 20, 2009, 02:35:47 pm »
https://studentforums.biz/index.php/topic,4384.0.html

Please look at my post which the link leads to..

Offline toobeerajpanchoo

  • SF Immigrant
  • **
  • Posts: 80
  • Reputation: 153
Re: Maths & Physics Help
« Reply #27 on: October 24, 2009, 11:57:10 am »
hi help in maths of cie
could u please provide me formula of how to calculate interior or exterior angle of a regular polygon and also how to calculate on kinematics PLEASE SOME OTHER ALSO FORMULAS USED IN MATHEMATICS THANKS :-[

Offline Ghost Of Highbury

  • O_o_O lala!
  • SF Farseer
  • *******
  • Posts: 4096
  • Reputation: 41428
  • Gender: Male
  • Namaskaram!
Re: Maths & Physics Help
« Reply #28 on: October 24, 2009, 12:09:07 pm »
hi help in maths of cie
could u please provide me formula of how to calculate interior or exterior angle of a regular polygon and also how to calculate on kinematics PLEASE SOME OTHER ALSO FORMULAS USED IN MATHEMATICS THANKS :-[

if n=number of sides

interior angle = ((n-2)*180)/n


which kinematics formula u want exactly?

v=u + at
s = ut + 0.5at2

v2 = u2 + 2as

s = (u+v)t/2
divine intervention!

Offline wassup

  • SF Citizen
  • ***
  • Posts: 259
  • Reputation: 384
  • Gender: Male
Re: Maths & Physics Help
« Reply #29 on: October 24, 2009, 12:09:47 pm »
hi help in maths of cie
could u please provide me formula of how to calculate interior or exterior angle of a regular polygon and also how to calculate on kinematics PLEASE SOME OTHER ALSO FORMULAS USED IN MATHEMATICS THANKS :-[

n=No. of sides

Sum of interior angles=180(n-2)

One interior angle=Sum of interior angles/n

One exterior angle=180o-One interior angle