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help needed..its urgent!!!!histograms
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Topic: help needed..its urgent!!!!histograms (Read 2570 times)
vids
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Posts: 40
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help needed..its urgent!!!!histograms
«
on:
May 18, 2009, 06:52:07 am »
maths p4
nov 03 q 8(b)
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vids
Newbie
Posts: 40
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Re: help needed..its urgent!!!!histograms
«
Reply #1 on:
May 18, 2009, 06:54:09 am »
histograms?
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MissDE
SF Citizen
Posts: 227
Reputation: 105
Re: help needed..its urgent!!!!histograms
«
Reply #2 on:
May 18, 2009, 07:11:42 am »
I really would like to help but am not sure
I think we have to first make the table:
less than 10
less than 15
less than 20
...............................
sry for not helping the way you need
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astarmathsandphysics
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Free the exam papers!
Re: help needed..its urgent!!!!histograms
«
Reply #3 on:
May 18, 2009, 07:35:36 am »
Find frquency densities by dividing frequencies by the lengths in the intervals
Length Frequency density
0-10 12/10=1.2
10-15 32/5=6.4
15-20 28/5=5.6
20-25 24/5=4.8
25-40 24/15=1.6
Now draw bars, Length on the x axis and frequency density on the y axis. Make sure you get even scales.
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Ghost Of Highbury
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Re: help needed..its urgent!!!!histograms
«
Reply #4 on:
May 18, 2009, 07:55:26 am »
RANGE :0<m<=10 10<M<=15 15<M<=20 20<M<=25 25<M<=40
WIDTH : 10 5 5 5 15
FREQU.: 12 32 28 24 25
THE SCALE 2cm - 5 kg
1cm - 2.5kg
the standard width taken is 2.5
now...
---------------------RULE------------------------------------------------------------------
if class width = n * standars width, then the height of the rectangle = frequency/n
---------------------------------------------------------------------------------------------
for the 1st.) 10 = n * 2.5 ...therefore n = 4 => height = 12/4 =
3
2nd.) 5 = n * 2.5....therefore n = 2 => height = 32/3 =
16
3rd.) 5 = n * 2.5....therefore n = 2 => height = 28/2 =
14
4th.) 5 = n * 2.5....therefore n = 2 => height = 24/2 =
12
5th.) 15 = n * 2.5....therefore n = 6 =>height = 24/6 =
4
v have been taught this method
is this correct.
plz chk the markscheme
i don't have it
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astarmathsandphysics
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Re: help needed..its urgent!!!!histograms
«
Reply #5 on:
May 18, 2009, 07:57:06 am »
No the height is the freoency dividing by the length of the interval so for the first one the height is 12/10=1.2
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astarmathsandphysics
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Re: help needed..its urgent!!!!histograms
«
Reply #6 on:
May 18, 2009, 07:58:21 am »
The height is called the frequency density for histograms.
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Ghost Of Highbury
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Re: help needed..its urgent!!!!histograms
«
Reply #7 on:
May 18, 2009, 08:01:59 am »
ohh..
thanks a lot
By the way...wat does the markscheme say..
can u plz upload it
i don't have it
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sweetsh
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Re: help needed..its urgent!!!!histograms
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Reply #8 on:
May 18, 2009, 08:02:30 am »
www.freeexampapers.com
?
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Ghost Of Highbury
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Re: help needed..its urgent!!!!histograms
«
Reply #9 on:
May 18, 2009, 08:05:35 am »
ohh..yaa..i'll try in that...
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astarmathsandphysics
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Re: help needed..its urgent!!!!histograms
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Reply #10 on:
May 18, 2009, 08:06:15 am »
The ms is there but is in 1 file for all the papers.
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astarmathsandphysics
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Re: help needed..its urgent!!!!histograms
«
Reply #11 on:
May 18, 2009, 08:07:26 am »
Hey sweetsh your avater is really good!
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sweetsh
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Re: help needed..its urgent!!!!histograms
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Reply #12 on:
May 18, 2009, 08:08:59 am »
Haha! Nice idea right?
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Ghost Of Highbury
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Re: help needed..its urgent!!!!histograms
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Reply #13 on:
May 18, 2009, 08:09:25 am »
i got the markscheme ..
it says..
1 mark for - horizontal scale 2cm = 5cm
1 mark for - k =1
5 marks for the heights - 3k, 16k, 14k, 12k, 4k
??
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astarmathsandphysics
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Re: help needed..its urgent!!!!histograms
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Reply #14 on:
May 18, 2009, 08:10:00 am »
Where did you get it? I might get one.
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help needed..its urgent!!!!histograms