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Author Topic: CHEM AND BIO HELP AND TIPS HERE  (Read 357463 times)

Offline 8T

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3000 on: June 06, 2010, 07:49:04 pm »
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Offline NidZ- Hero

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3001 on: June 06, 2010, 07:49:57 pm »
Quote from: ~VIN1094~ on June 06, 2010, 07:34:50 pm
Um, in my book for cracking its 540*C :-\ and yeah typo Al2O3 ;)
450C-750C
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Offline 8T

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3002 on: June 06, 2010, 07:56:22 pm »
In o/n 09 paper 32 q 6 c the total number of moles of gases why is it 0.08 i thought it would be 0.04 explain please quickly???
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Offline 8T

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3003 on: June 06, 2010, 07:58:25 pm »
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Offline WARRIOR

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3004 on: June 06, 2010, 08:01:26 pm »
Quote from: 8T on June 06, 2010, 07:56:22 pm
In o/n 09 paper 32 q 6 c the total number of moles of gases why is it 0.08 i thought it would be 0.04 explain please quickly???
first you find the moles of fe2o3 which is  .08


and thn the ration of moles of gases = 2: 1 therfore .04

and there are two gases

so . 04 + .04
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Offline 8T

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3005 on: June 06, 2010, 08:03:56 pm »
Quote from: Kimo Jesus on June 06, 2010, 08:01:26 pm
first you find the moles of fe2o3 which is  .08


and thn the ration of moles of gases = 2: 1 therfore .04

and there are two gases

so . 04 + .04
Fe2o3 is 0.04 not 0.08 .. soo?
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Offline WARRIOR

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3006 on: June 06, 2010, 08:06:09 pm »
Quote from: 8T on June 06, 2010, 08:03:56 pm
Fe2o3 is 0.04 not 0.08 .. soo?
sorry i meant fe2so4

12.16 /152
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Offline Vin

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3007 on: June 06, 2010, 08:47:59 pm »
c)

1. 12.16/152 g= 0.08 moles

2. Molar ratio
= 2 : 1
= 0.08 : x
so x= 0.04

3. 56+56+16+16+16 = 160g

4.  moles = mass/mass of 1 mole

mass = 0.04 * 160
=6.4g

5. two gases so 0.04 + 0.04 = 0.08mol

6. vol of gas = 0.08 * 24
= 1.92
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Offline $H00t!N& $t@r

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3008 on: June 06, 2010, 09:15:39 pm »
ok i have a silly question...  :-[      s05 q2c (i)  
how do u knw which one is in excess?
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Offline The InViSiBlE GIrl (Eva)

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3009 on: June 06, 2010, 09:20:09 pm »
Quote from: CatAly$t on June 05, 2010, 08:13:46 pm
somebody pls explain to me this...
Hey Ya could someone pls do this question its really wierd cant figure it out at all
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Offline The InViSiBlE GIrl (Eva)

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3010 on: June 06, 2010, 09:20:41 pm »
Quote from: CatAly$t on June 05, 2010, 08:13:46 pm
somebody pls explain to me this...
Hey Ya could someone pls do this question its really wierd cant figure it out at all
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Offline $H00t!N& $t@r

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3011 on: June 06, 2010, 09:29:49 pm »
Quote from: Dizzy on June 06, 2010, 09:20:41 pm
Hey Ya could someone pls do this question its really wierd cant figure it out at all

lol wheres the question?
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Offline The InViSiBlE GIrl (Eva)

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3012 on: June 06, 2010, 09:31:22 pm »
Hey smart guy can u pls solve this question for me really cant understand it The link is just below this line.
Quote from: CatAly$t on June 05, 2010, 07:13:46 PM
Quote from: ~VIN1094~ on June 06, 2010, 08:47:59 pm

c)

1. 12.16/152 g= 0.08 moles

2. Molar ratio
= 2 : 1
= 0.08 : x
so x= 0.04

3. 56+56+16+16+16 = 160g

4.  moles = mass/mass of 1 mole

mass = 0.04 * 160
=6.4g

5. two gases so 0.04 + 0.04 = 0.08mol

6. vol of gas = 0.08 * 24
= 1.92
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Offline The InViSiBlE GIrl (Eva)

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3013 on: June 06, 2010, 09:33:05 pm »
Hey smart guy can u pls solve this question for me really cant understand it The link is just below this line.
Quote from: CatAly$t on June 05, 2010, 07:13:46 PM
Quote from: ~VIN1094~ on June 06, 2010, 08:47:59 pm

c)

1. 12.16/152 g= 0.08 moles

2. Molar ratio
= 2 : 1
= 0.08 : x
so x= 0.04

3. 56+56+16+16+16 = 160g

4.  moles = mass/mass of 1 mole

mass = 0.04 * 160
=6.4g

5. two gases so 0.04 + 0.04 = 0.08mol

6. vol of gas = 0.08 * 24
= 1.92
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Offline Vin

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Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #3014 on: June 06, 2010, 09:40:43 pm »
Quote from: Shooting Star on June 06, 2010, 09:15:39 pm
ok i have a silly question...  :-[      s05 q2c (i)  
how do u knw which one is in excess?

OK look at the graph, mass of the plate is constant after some time. What does it mean? No more Zn is reacting, right? So the reaction is finished. Therefore Zn is excess as it is still left after the reaction is over. Got it?
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