Got a doubt from the 2005 m/j paper 3 chemistry paper.
When 0.015 moles of iodine react with 0.045 moles of chlorine to form 0.030 moles of a single product. So, we have to complete the equation. The answer is:
I2 + 3Cl2 = 2ICl3 my question is how come theres 3 atms of Cl formed?
Oh and second question....when iodine reacts with zinc nd wen u decrease the concentration of iodine how come less of zinc is used up?
sincec ration is 1 : 3 : 2
and we normally get ICL
but since it is 2 ICL , we have have now 2 i odines and 2 chlorines
now we have to balance , 2 iodines on the left
but thre are 6 clhorines on the left and honly two on the right , so we have to change the cl into CL3
less concentraion = less molecules per unite volume , less molecules = less reaction , so less zinc gets used up
