Author Topic: CHEM AND BIO HELP AND TIPS HERE  (Read 358341 times)

holtadit

  • Guest
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2385 on: June 02, 2010, 09:01:59 am »
i really dont understand anything in moles......can some1 gimme a site where they explain how to calculate moles easily? thanks.

http://thenightdreamer.wordpress.com/2010/03/19/moles/

The link takes you to my website. It may help you.

Like I said post a question you dont understand and we'll help you ;)

Offline guMnam

  • !!~~**~~!!
  • SF Farseer
  • *******
  • Posts: 4242
  • Reputation: 12471
  • Gender: Male
  • !!~~guMnam~~!!
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2386 on: June 02, 2010, 11:04:20 am »
Thanks

I <3 Challenges
Never give up :)

Offline basharooo

  • Newbie
  • *
  • Posts: 19
  • Reputation: 0
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2387 on: June 02, 2010, 12:45:30 pm »
guys this question is freaking me out ( it is from igcse study guide for chemistry ,
about stoichiometry pg31

sample q 5
calcaluate the volume of sodium hydroxide , concentration of 0.16 mol/dm3 , needed to neutralise 20 cm3
of sulphric acid , concentration  0.2 mol/dm3 .

the eqation is 2NaOH+H2SO4--->Na2SO4+H20
-------------------------------------------------------
the answer is moles of H2SO4 = 20 divided by 10000 * 0.2 = 0.004
?????

know why divided by 10000 ??????????????????????????? ??? :-\



 

Offline Vin

  • SF V.I.P
  • ********
  • Posts: 7914
  • Reputation: 52609
  • Gender: Male
    • Theory of Life - A new skew.
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2388 on: June 02, 2010, 12:52:10 pm »
to convert cm3 to dm3 (decimeter cube) ...  dm3  is used ALWAYS ;)

Offline basharooo

  • Newbie
  • *
  • Posts: 19
  • Reputation: 0
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2389 on: June 02, 2010, 12:57:56 pm »
to convert cm3 to dm3 (decimeter cube) ...  dm3  is used ALWAYS ;)

yea but isn't 1dm3=1000cm3
so 20cm3 *1dm3 divided by 1000 will not give 10000dm3 ?????
 ???

Offline Ivo

  • SF Geek
  • ****
  • Posts: 515
  • Reputation: 2767
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2390 on: June 02, 2010, 01:00:46 pm »
guys this question is freaking me out ( it is from igcse study guide for chemistry ,
about stoichiometry pg31

sample q 5
calcaluate the volume of sodium hydroxide , concentration of 0.16 mol/dm3 , needed to neutralise 20 cm3
of sulphric acid , concentration  0.2 mol/dm3 .

the eqation is 2NaOH+H2SO4--->Na2SO4+H20
-------------------------------------------------------
the answer is moles of H2SO4 = 20 divided by 10000 * 0.2 = 0.004
?????

know why divided by 10000 ??????????????????????????? ??? :-\



 

Moles of sulphuric acid = 0.2*0.02=0.004

Moles of sodium hydroxide = 0.004*2=0.008

Volume of sodium hydroxide = 0.008/0.16=0.05dm3 or 50cm3
« Last Edit: June 02, 2010, 01:07:44 pm by Ivo »
Always willing to help!  8)
"In helping others, we shall help ourselves, for whatever good we give out completes the circle and comes back to us."

Offline Ivo

  • SF Geek
  • ****
  • Posts: 515
  • Reputation: 2767
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2391 on: June 02, 2010, 01:01:54 pm »
yea but isn't 1dm3=1000cm3
so 20cm3 *1dm3 divided by 1000 will not give 10000dm3 ?????
 ???

Since it's from a textbook, there are always typos :P.  I can confirm to convert cm3 to dm3, you divide by 1000.  So the book is wrong :D
Always willing to help!  8)
"In helping others, we shall help ourselves, for whatever good we give out completes the circle and comes back to us."

Offline basharooo

  • Newbie
  • *
  • Posts: 19
  • Reputation: 0
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2392 on: June 02, 2010, 01:03:49 pm »
Moles of sulphuric acid = 0.2*0.02

Moles of sodium hydroxide = 0.02*2=0.04

Volume of sodium hydroxide = 0.04/0.16=0.25dm3

THX BUT THE ANSWER IN MY BOOK SAYS O.05 DM3 AND U ANSWER WILL BE 0.25?

Offline Ivo

  • SF Geek
  • ****
  • Posts: 515
  • Reputation: 2767
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2393 on: June 02, 2010, 01:06:33 pm »
THX BUT THE ANSWER IN MY BOOK SAYS O.05 DM3 AND U ANSWER WILL BE 0.25?

Sorry my mistake.  I've edited the post.

Moles of sulphuric acid = 0.2*0.02=0.004

Moles of sodium hydroxide = 0.004*2=0.008

Volume of sodium hydroxide = 0.008/0.16=0.05dm3 or 50cm3
« Last Edit: June 02, 2010, 01:08:13 pm by Ivo »
Always willing to help!  8)
"In helping others, we shall help ourselves, for whatever good we give out completes the circle and comes back to us."

Offline Vin

  • SF V.I.P
  • ********
  • Posts: 7914
  • Reputation: 52609
  • Gender: Male
    • Theory of Life - A new skew.
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2394 on: June 02, 2010, 01:08:01 pm »
Sorry my mistake.  I've edited the post.

Exactly I was kinda wondering ...

Offline basharooo

  • Newbie
  • *
  • Posts: 19
  • Reputation: 0
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2395 on: June 02, 2010, 01:11:10 pm »
THX :D

Offline Ivo

  • SF Geek
  • ****
  • Posts: 515
  • Reputation: 2767
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2396 on: June 02, 2010, 01:28:23 pm »
I've included some information about salt preparations, I hope this is useful for you.
Always willing to help!  8)
"In helping others, we shall help ourselves, for whatever good we give out completes the circle and comes back to us."

Offline High-R

  • SF Geek
  • ****
  • Posts: 303
  • Reputation: 65535
  • Gender: Male
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2397 on: June 02, 2010, 01:50:54 pm »
I've included some information about salt preparations, I hope this is useful for you.
Thanks for this dude!!! ;)
ur awsum!!...=D
 :D :D

Offline 7ooD

  • SF Geek
  • ****
  • Posts: 427
  • Reputation: 713
  • Gender: Male
    • 7ood
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2398 on: June 02, 2010, 03:17:26 pm »
i have a quick question the formula for acids is cnh2n+1 cooh but i read that there is a new formula which works the same cnh2n o2 how can it be the same
pimpin ain't dead it just moved to the web



Offline Ivo

  • SF Geek
  • ****
  • Posts: 515
  • Reputation: 2767
Re: CHEM AND BIO HELP AND TIPS HERE
« Reply #2399 on: June 02, 2010, 03:37:23 pm »
i have a quick question the formula for acids is cnh2n+1 cooh but i read that there is a new formula which works the same cnh2n o2 how can it be the same

I don't see how the second one can possibly work.  It is definitely CnH2n+1COOH.

The functional group is -COOH so I can't see how that can change.
Always willing to help!  8)
"In helping others, we shall help ourselves, for whatever good we give out completes the circle and comes back to us."