thx...
and the last page please....i really su*k in mole calculations ...if possible,with some explanations pls....
thx
The equation you need to use is:
Volume of gas (in dm
3)
Moles of gas = --------------------------
24
Note to convert cm
3 to dm
3, divide quantity by 1000 (e.g. 20cm
3/1000=0.02dm
3)
This is the proper theory and equation behind my calculations below.
Here are the answers for 5) c) as requested:
i) Moles of C
4H
6: 0.02/24=0.000833
From equation, we know 2 moles of C
4H
6 reacts with 11 moles of O
2 Therefore, moles of O
2: 0.000833*5.5=0.00458
Therefore, volume of O
2: 4.58*24*1000=
110cm3ii) From equation, we know 2 moles of C
4H
6 produces 8 moles of CO
2 Therefore, moles of CO
2: 0.000833*4=0.00333
Therefore, volume of CO
2: 0.00333*24*1000=
80cm3iii) From equation, we know 2 moles of C
4H
6 produces 6 moles of H
2O
Therefore, moles of H
2O: 0.000833*3=0.0025
Therefore, volume of H
2O: 0.0025*24*1000=60
Therefore, total volume of gases is simply volume of CO
2 + volume of H
2O:
80+60=
140cm3 Alternatively, 8+6=14, so 2 moles of C
4H
6 produces 14 moles of products
Therefore, moles of products: 0.000833*7=0.00583
Therefore, volume of products: 0.00583*24*1000=
140cm3For part d), you use this formula:
Mass
Moles = ------
M
rd) From the above equation, 1 mole of butyne forms 3 moles of water
Number of moles of butyne reacted: 9/54=
0.167 Number of moles of water formed: 0.167*3=
0.5 Mass of water formed: 0.5*(2+16)=
9gI hope this has helped.