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Ghost Of Highbury:
for 4biii)

the reaction

AlCl3 + 3NaOH --> Al(OH)3 + 3NaCl

Al(OH)3 is insoluble (precipitated), however, when all AlCl3 is reacted, the excess NaOH that is added reacts with Al(OH)3

Al(OH)4- ions are formed in the presence of high concentrations of hydroxide: this is soluble. Thus all the precipitate dissolves and the height of the precipitate becomes 0. for the graph, just draw a rough graph where it continues till the maximum point but falles to 0 when excess is added.

Ghost Of Highbury:
hope u understood.  :)

$!$RatJumper$!$:
guys whats the formula to calculate percentage yeild?

cooldude:

--- Quote from: $!$RatJumper$!$ on November 11, 2009, 07:23:18 pm ---guys whats the formula to calculate percentage yeild?

--- End quote ---

(actual yield/theoretical yield)*100

~~~~shreyapril~~~~:
enjoyed chem ;)

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