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@d!_†oX!©:
that's paper 1...
what do u mean by 4 b 2 and 4 b 3??????????

~~~~shreyapril~~~~:
this is MCQ question!!
how can you expect 4b2 and 4b3???

adorabledaughter_07:
@aditoxic- oh got it..din notiz dat..thankz! :)

ruchir.sakhrani:
sorry guyz
It is paper 3
http://www.freeexampapers.com/FreeExamPapers.com_.php?__lo=SUdDU0UvQ2hlbWlzdHJ5L0NJRS8yMDA0IEp1bi8wNjIwX3MwNF9xcF8zLnBkZg==

Ghost Of Highbury:
4bii) first understand the q.

       FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl

moles of FeCl3 = conc. * volume = 1 * 4/1000 = 0.004

MOles of NaOH = 0.004*3 = 0.012 or conc. * volume = 1 * 12/1000 (look at graph)  = 0.012

when FeCl2 is used, this is the equation

FeCl2 + 2NaOH --> Fe(OH)2 + 2NaCl

Moles of FeCl2 = conc. * volume = 0.004

but here, the mole ratio is 1:2

so the moles of NaOH = 0.004 * 2 = 0.008

volume = moles/conc. = 0.008/1 = 0.008dm^3 = 8cm^3

thus, for FeCl2 --> 8cm^3 of NaOH reacts completely with FeCl2, so, the shape wud be same, only it wud become constant (parallel to x-axis) at 8cm^3 of NaOH

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