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CHEM AND BIO HELP AND TIPS HERE

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eightAs:

--- Quote from: @d!_†oX!© on November 10, 2009, 02:55:03 pm ---ok people..here i am again...

Tungsten metal, W, is manufactured by reducing tungsten(III)oxide, WO3, whit carbon.

WO3 + 3C -----> 3CO + W

Calculate the mass of carbon needed to reduce 116g of tungsten(III)oxide.

-------------------------------------------------------------------------------------------------------------------------------
Now, I know how to do it.
We first take out the number of moles of WO3
which comes out to be 116/232 = 0.5 moles
Then, as the ratio is 1:3
Thus, the number of moles of C = 0.5*3 = 1.5 moles
Thus, the mass of carbon = 1.5*12 = 18g

Now my question,
if the ratio according to the equation is 1:3 for WO3:C
The how is it possible that for 116g of WO3 only 18g of C is required?

So, i thought maybe i have done it wrong although this is the correct method itself, but i still tried
Having the mass of WO3 as 116g and the ratio being 1:3
thus, the mass of C be 3*116 = 348g

But, the second method is wrong, isn't it?
then how are we getting 18g as the mass of Carbon required??

Please help guys!!!


--- End quote ---
This part is wrong. Mole ratio is 3:1 not the mass ratio. Hence, the second method is wrong.

@d!_†oX!©:
dude i know the second part is wrong...i have already stated that....bt now tell me how can the first part be correct??
how can ther be only 18g of C to reduce 116g of WO3

~~~~shreyapril~~~~:
now i have a meathod!!
if 1:3 rite??
1:3::116:x

so x=348 grams!!

check for the ans!!

Ghost Of Highbury:
arre shrey that answer is rong,

@adi - dude see,

232g of WO3 reacts with 36g of C rite?

so 116g with 18g of C

y do u find the answer weird, ??  check the ratio

232-36
116-18

looks quite clear to me..

@d!_†oX!©:
ohhhh shrey!!!u back again with ur faltu replies.....
this has already been proved wrong....this method is wrong...read the question for what exactly m asking b4 replying...

nd y do u relate everything in the world with a ratio??

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