ok people..here i am again...
Tungsten metal, W, is manufactured by reducing tungsten(III)oxide, WO3, whit carbon.
WO3 + 3C -----> 3CO + W
Calculate the mass of carbon needed to reduce 116g of tungsten(III)oxide.
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Now, I know how to do it.
We first take out the number of moles of WO3
which comes out to be 116/232 = 0.5 moles
Then, as the ratio is 1:3
Thus, the number of moles of C = 0.5*3 = 1.5 moles
Thus, the mass of carbon = 1.5*12 = 18g
Now my question,
if the ratio according to the equation is 1:3 for WO3:C
The how is it possible that for 116g of WO3 only 18g of C is required?
So, i thought maybe i have done it wrong although this is the correct method itself, but i still tried
Having the mass of WO3 as 116g and the ratio being 1:3
thus, the mass of C be 3*116 = 348g
But, the second method is wrong, isn't it?
then how are we getting 18g as the mass of Carbon required??
Please help guys!!!