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ok people..here i am again...Tungsten metal, W, is manufactured by reducing tungsten(III)oxide, WO3, whit carbon.WO3 + 3C -----> 3CO + WCalculate the mass of carbon needed to reduce 116g of tungsten(III)oxide.-------------------------------------------------------------------------------------------------------------------------------Now, I know how to do it.We first take out the number of moles of WO3which comes out to be 116/232 = 0.5 molesThen, as the ratio is 1:3Thus, the number of moles of C = 0.5*3 = 1.5 molesThus, the mass of carbon = 1.5*12 = 18gNow my question, if the ratio according to the equation is 1:3 for WO3:CThe how is it possible that for 116g of WO3 only 18g of C is required?So, i thought maybe i have done it wrong although this is the correct method itself, but i still triedHaving the mass of WO3 as 116g and the ratio being 1:3 thus, the mass of C be 3*116 = 348gBut, the second method is wrong, isn't it?then how are we getting 18g as the mass of Carbon required??Please help guys!!!
what difference does it make if it has a high Ar?i already said it myself that the first method is the right one...but the answer has to be a valid one dude...u cant just right 24/6=7 if your calci says so....
ohhhh shrey!!!u back again with ur faltu replies.....this has already been proved wrong....this method is wrong...read the question for what exactly m asking b4 replying...nd y do u relate everything in the world with a ratio??
arre shrey that answer is rong, @adi - dude see, 232g of WO3 reacts with 36g of C rite?so 116g with 18g of Cy do u find the answer weird, ?? check the ratio232-36116-18looks quite clear to me..