Note = [2] means to the power of 2
Q) The equation of the curve is y = 3cos2x. The equation of a line is x+2y=? (pi) . On the same Diagram, sketch the curve and the line for 0<x<? .
Find the first 3 terms in the expansion of (2-x)[2] in ascending power of x.
I did the graph but didnt know how to do the line! :S
Q)2cos? = 1/tan? 0<?<2?
I did upto cos?(2sin?-1)=0
so cos?=0 so
0and 2sin?-1=0 so
?/6 and
5?/6so now I have 3 answers which are in bold! how did ?/2 and 3?/2 come??
Q)sinx=3/5 and angle is obtuse. Find tanx and cosx
..........
Identities:
Q) (1+tan[2]?)cos[2]? = 1
Q) sin[2]?/1-cos? = 1+cos?
Q) 1-tan[2]?/1+tan[2]? = 1-2sin[2]?
.........
Q) Find the nature of the root? 2x[2] - ax + 2a[2] = 0
Q) x[2] - 2x + 1 = p(x-3) has equal roots find P??
i did b[2] - 4ac
(-2-p)(-2-p)-4(1)(1+3p) = 0
Thank you in advance!