« previous next »
Pages: 1 [2]   Go Down

Author Topic: Another question - HELP!  (Read 8545 times)

Offline NotAbod

  • Wikipedia Contributor
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3929
  • Reputation: 65535
  • Gender: Male
Re: Another question - HELP!
« Reply #15 on: May 15, 2011, 11:46:47 am »
Quote from: $~SauD~$ on May 15, 2011, 11:46:08 am
Take your time,
If you have doubt search the formula over net ;)
thanks :P
okay :P
Logged

Offline Ghost Of Highbury

  • O_o_O lala!
  • SF Farseer
  • *******
  • Posts: 4096
  • Reputation: 41428
  • Gender: Male
  • Namaskaram!
Re: Another question - HELP!
« Reply #16 on: May 15, 2011, 12:45:05 pm »
Volume of the pool = 1512m^3

1m^3 = 1000000cm^3
1512m^3 = 1512000000cm^3

The pipe transfers pi*12.5^2*14 = 6872cm^3/s

can be written as

6872cm^3 -> 1s
1512000000cm^3 (the whole pool to be transferred) -> ?

1512000000/6872 = 220023.3s

= 220023.3/60 = 3367minutes = 56.11 hours ~ 2.34 days
Logged
divine intervention!

Offline NotAbod

  • Wikipedia Contributor
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3929
  • Reputation: 65535
  • Gender: Male
Re: Another question - HELP!
« Reply #17 on: May 15, 2011, 12:51:37 pm »
220023.3/60 = 3367minutes ?
i get 3667m
Logged

Offline SauD~

  • Chére
  • SF V.I.P
  • ********
  • Posts: 8629
  • Reputation: 65535
  • Gender: Male
  • ~ I wish my dream comes true ~
Re: Another question - HELP!
« Reply #18 on: May 15, 2011, 12:57:11 pm »
Quote from: Ghost Of Highbury~ on May 15, 2011, 12:45:05 pm
Volume of the pool = 1512m^3

1m^3 = 1000000cm^3
1512m^3 = 1512000000cm^3

The pipe transfers pi*12.5^2*14 = 6872cm^3/s

can be written as

6872cm^3 -> 1s
1512000000cm^3 (the whole pool to be transferred) -> ?

1512000000/6872 = 220023.3s

= 220023.3/60 = 3367minutes = 56.11 hours ~ 2.34 days

By the way, Can you just help me by telling why aren't we using the speed value here when the formula is
"Flow of water(volume of whole water) = Cross sectional (volume of the pipe) x Speed x time "
thanks
Logged

Offline NotAbod

  • Wikipedia Contributor
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3929
  • Reputation: 65535
  • Gender: Male
Re: Another question - HELP!
« Reply #19 on: May 15, 2011, 01:05:56 pm »
ok here is the answer:
rate of flow per second = pi*12.5^2 * 14 = 6872 cm^3
time in seconds = (1512*100^3) / 6872 = 220023 seconds.
220023/ (3600*24) = 2.54 days.
0,54 * 24 = 13 hours
answer is 2days 13 hours.
same as ghost calcs :)
Logged

Offline SauD~

  • Chére
  • SF V.I.P
  • ********
  • Posts: 8629
  • Reputation: 65535
  • Gender: Male
  • ~ I wish my dream comes true ~
Re: Another question - HELP!
« Reply #20 on: May 15, 2011, 01:08:13 pm »
Quote from: AboD on May 15, 2011, 01:05:56 pm
ok here is the answer:
rate of flow per second = pi*12.5^2 * 14 = 6872 cm^3
time in seconds = (1512*100^3) / 6872 = 220023 seconds.
220023/ (3600*24) = 2.54 days.
0,54 * 24 = 13 hours
answer is 2days 13 hours.
same as ghost calcs :)
Just someone plz explain me why is everyone excluding the speed value -_____________-

Logged

Offline NotAbod

  • Wikipedia Contributor
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3929
  • Reputation: 65535
  • Gender: Male
Re: Another question - HELP!
« Reply #21 on: May 15, 2011, 01:09:48 pm »
Quote from: $~SauD~$ on May 15, 2011, 01:08:13 pm
Just someone plz explain me why is everyone excluding the speed value -_____________-


i used speed.
Rate of flow per second = pipe cross section area * speed
Logged

Offline SauD~

  • Chére
  • SF V.I.P
  • ********
  • Posts: 8629
  • Reputation: 65535
  • Gender: Male
  • ~ I wish my dream comes true ~
Re: Another question - HELP!
« Reply #22 on: May 15, 2011, 01:30:20 pm »
Quote from: AboD on May 15, 2011, 01:09:48 pm
i used speed.
Rate of flow per second = pipe cross section area * speed
you used length not speed,
volume requires length!
Logged

Offline NotAbod

  • Wikipedia Contributor
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3929
  • Reputation: 65535
  • Gender: Male
Re: Another question - HELP!
« Reply #23 on: May 15, 2011, 01:34:22 pm »
Quote from: $~SauD~$ on May 15, 2011, 01:30:20 pm
you used length not speed,
volume requires length!
reread the question
cylinder hight is 14
speed is also 14.
i use the speed to find flow per second
Logged

Offline hasan919

  • Newbie
  • *
  • Posts: 7
  • Reputation: 21
Re: Another question - HELP!
« Reply #24 on: May 15, 2011, 01:42:14 pm »
Ahhh, thanks alot guys. i get it ;]
Logged

Offline SauD~

  • Chére
  • SF V.I.P
  • ********
  • Posts: 8629
  • Reputation: 65535
  • Gender: Male
  • ~ I wish my dream comes true ~
Re: Another question - HELP!
« Reply #25 on: May 15, 2011, 01:45:30 pm »
Quote from: AboD on May 15, 2011, 01:34:22 pm
reread the question
cylinder hight is 14
speed is also 14.
i use the speed to find flow per second
and if the question included values like:
8 height and speed is 16
so will we use value of speed as 2?
Logged

Offline NotAbod

  • Wikipedia Contributor
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3929
  • Reputation: 65535
  • Gender: Male
Re: Another question - HELP!
« Reply #26 on: May 15, 2011, 01:47:09 pm »
Quote from: $~SauD~$ on May 15, 2011, 01:45:30 pm
and if the question included values like:
8 height and speed is 16
so will we use value of speed as 2?

Rate of flow = cross section area x speed.
use 16
Logged

Offline Ghost Of Highbury

  • O_o_O lala!
  • SF Farseer
  • *******
  • Posts: 4096
  • Reputation: 41428
  • Gender: Male
  • Namaskaram!
Re: Another question - HELP!
« Reply #27 on: May 16, 2011, 07:43:15 am »
Quote from: AboD on May 15, 2011, 12:51:37 pm
220023.3/60 = 3367minutes ?
i get 3667m
My bad, typo.
Logged
divine intervention!
Pages: 1 [2]   Go Up
« previous next »