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Author Topic: statistics  (Read 3924 times)

Offline Arthur Bon Zavi

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Re: statistics
« Reply #15 on: May 03, 2011, 01:51:00 pm »
Quote from: AboD on May 03, 2011, 11:25:14 am
Welcome back fidato :D

Thanks.

You both - substitute the values and check, (i.e. sq.rt. of 0.42 and subtract the answer from 1 and hence square, this will give you the probability of loosing two in a row).

Get my point ?
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Offline NotAbod

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Re: statistics
« Reply #16 on: May 03, 2011, 01:58:41 pm »
nope, didnt get it
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Offline NotAbod

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Re: statistics
« Reply #17 on: May 03, 2011, 02:00:21 pm »
explain this point please
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Offline Arthur Bon Zavi

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Re: statistics
« Reply #18 on: May 03, 2011, 02:10:27 pm »
I think question has faulty values.

Okay, study this :

If you don't understand, then tell me.
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Offline NotAbod

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Re: statistics
« Reply #19 on: May 03, 2011, 02:22:33 pm »
if prob. of winning is 1-sq0.28
then winning both is  [1-sq0.28] * [1-sq0.28] = 0.22 ?
not sure from this
chatroom?
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Offline SkyPilotage

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Re: statistics
« Reply #20 on: May 03, 2011, 02:37:37 pm »
Quote from: Fidato on May 03, 2011, 02:10:27 pm
I think question has faulty values.

Okay, study this :

If you don't understand, then tell me.
Ahaha Fidato, Very good point :) but you would be correct if you are sure that tht probability is independant... but its not!!
This means that the prob of winning the first time is DIFFERENT than the probabiity of winning the second game!!!!
Got it?  :)                      P.S: if you aren't convinced try finding the prob of winning exaclty one game it will come up as 0.5 not 0.3...
Life is simple, no need to go all through this  ;)
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Offline NotAbod

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Re: statistics
« Reply #21 on: May 03, 2011, 02:39:22 pm »
maybe that dude copied the wrong values
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Offline SkyPilotage

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Re: statistics
« Reply #22 on: May 03, 2011, 02:42:11 pm »
Quote from: AboD on May 03, 2011, 02:39:22 pm
maybe that dude copied the wrong values
Everything is possible but it wont matter  ;D
Use the values you have...I am pretty sure the probabilities aren't the same in the first and second time  :-\
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Offline Arthur Bon Zavi

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Re: statistics
« Reply #23 on: May 03, 2011, 04:11:52 pm »
Quote from: SkyPilotage on May 03, 2011, 02:37:37 pm
Ahaha Fidato, Very good point :) but you would be correct if you are sure that tht probability is independant... but its not!!
This means that the prob of winning the first time is DIFFERENT than the probabiity of winning the second game!!!!
Got it?  :)                      P.S: if you aren't convinced try finding the prob of winning exaclty one game it will come up as 0.5 not 0.3...
Life is simple, no need to go all through this  ;)

You came to my point. ;)
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Offline Arthur Bon Zavi

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Re: statistics
« Reply #24 on: May 03, 2011, 04:15:56 pm »
Quote from: SkyPilotage on May 03, 2011, 02:37:37 pm
Ahaha Fidato, Very good point :) but you would be correct if you are sure that tht probability is independant... but its not!!
This means that the prob of winning the first time is DIFFERENT than the probabiity of winning the second game!!!!Got it?  :)                      P.S: if you aren't convinced try finding the prob of winning exaclty one game it will come up as 0.5 not 0.3...
Life is simple, no need to go all through this  ;)

Think on this again. If probabilities of winning the first and second games would be different, then lossing both the games would not be (sq.rt. 0.28).
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Offline SkyPilotage

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Re: statistics
« Reply #25 on: May 03, 2011, 04:30:42 pm »
Quote from: Fidato on May 03, 2011, 04:15:56 pm
Think on this again. If probabilities of winning the first and second games would be different, then lossing both the games would not be (sq.rt. 0.28).
You mean the probability of losing one game would not be sq.rt of 0.28? Exactly but why do we care  ::)
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