yes let me explain and answer this.
wat r all the chances in this game?
1-win both
2-lose both
3-win first, lose second
4-lose first, win second
probability of winning exactly one is given: 0.3, this include chance 3 and 4
probability of losing both is given: 0.28
sum of probabilities always add up to 1
let probability of winning both = y
0.28 + 0.3 + y = 1
y = 1- (0.28 + 0.3)
y = 0.42
probability of winning both is 0.42