Hey EMO123
Here is the solution to ur query:
(1+ax)^n = 1+36x+576x^2
1+n(ax)+[n(n-1)(ax)^2]/2! = 1+36x+576x^2
na=36
n= 36/a
subsitute 36/a for n
[36/a(36/a-1)a^2] divide by 2 factorial and this equals to 576
and u'll end up with an equation
(1296a-36a^2)/a=1152
36a^2+1152a-1296a=0
a(36a-144)=0
36a=144
a=4 n=36/4
n=9HOPE THIS HELPS