Practice and you'll get used to it eventually. (:
gradient of line y=3x-2 is 3 b/c in y=mx+c form m is the gradient.
So now we have to find the point on the curve where gradient is 3.
dy/dx= 4x-1
tangent to curve parallel where 4x-1=3
4x=4
x=1
at x=1, y=2-1-1=0
therefore coordinates should be (1,0)
(: