who have answers to this book???(edexcel)

[~ Miss Relina ~]

guys anybody who have answrs to chemistry book inthis link plz help
http://www.amazon.co.uk/Edexcel-Chemistry-Student-Level-Sciences/dp/1405896353
plz plz plz need it asap help as much as u can I have  exams soon     for edexcel

[Deadly_king]

guys anybody who have answrs to chemistry book inthis link plz help
http://www.amazon.co.uk/Edexcel-Chemistry-Student-Level-Sciences/dp/1405896353
plz plz plz need it asap help as much as u can I have  exams soon     for edexcel

Am sorry but I don't have the answers. 

Nevertheless, if you need them so much, you could post the questions here and i'll work them out such that we can compare answers.

[elemis]

It should have come with a CD-ROM i.e. a LiveText.

There should be answers in it, I think.

[The Golden Girl =D]

guys anybody who have answrs to chemistry book inthis link plz help
http://www.amazon.co.uk/Edexcel-Chemistry-Student-Level-Sciences/dp/1405896353
plz plz plz need it asap help as much as u can I have  exams soon     for edexcel

I have the exact book but Unfortunately I never found the Answers -.- tho the CGP Guide for it is incredible it has Qs and Answers at the back

I assume you're solving the Questions in the book , it's Okay take a screen shot of your doubt *from the CD* and Post it over here , We'll help ya  

Good Luck

[~ Miss Relina ~]

I have the exact book but Unfortunately I never found the Answers -.- tho the CGP Guide for it is incredible it has Qs and Answers at the back

I assume you're solving the Questions in the book , it's Okay take a screen shot of your doubt *from the CD* and Post it over here , We'll help ya  

Good Luck

well I have questions but cando the screen shot so I will give u the page 23 Q3 if u could do it telll me ? if u donot tell mwe to post it here

many Thanks

[The Golden Girl =D]

well I have questions but cando the screen shot so I will give u the page 23 Q3 if u could do it telll me ? if u donot tell mwe to post it here

many Thanks

I'll working on it

I got a)  0.03211  for C , 0.003699 for N , 0.2247 for H , and 0.06033 for O

b) as 9 : 1 : 61 : 16

c) as C9NH61O

d) I didn't know how to solve it  *srry I'm distracted by the TV -.- *

here is the pic ppl


 

[Deadly_king]

Here's my working.

a) Make use of the formula ---> No of moles = Mass/Mr
Oxygen : 0.66712/16 = 0.041695
Carbon : 0.3853/12 = 0.032108
Hydrogen : 0.05178/1 = 0.05178
Nitrogen : 0.2247/14 = 0.01605
Phosphorus : 0.2981/31 = 0.0096161

b) To get the ratio, we divide everything by the smallest number which in this case is 0.0096161.

Example : Oxygen -----> 0.041695/0.0096161 = 13/3(nearest)
So the ratio is O    : C      : H      : N     : P
                  13/3  : 10/3 : 16/3  : 5/3   : 1

Now we just have to multiply by 3 to get C₁₀O₁₃N₅H₁₆P₃. This is the empirical formula.

d) The empirical formula gives us an Mr of 494.

494n = 507 which is almost n=1.

Hence the molecular formula is equal to the empirical one.

Molecular formula : C₁₀O₁₃N₅H₁₆P₃

[~ Miss Relina ~]

I'll working on it

I got a)  0.03211  for C , 0.003699 for N , 0.2247 for H , and 0.06033 for O

b) as 9 : 1 : 61 : 16

c) as C9NH61O

d) I didn't know how to solve it   *srry I'm distracted by the TV -.- *

here is the pic ppl


 

Thanks that is great  
how did u took the screen shot pm me   other wise I wonot be able to post my questions as they are too long to type 

[~ Miss Relina ~]

Here's my working.

a) Make use of the formula ---> No of moles = Mass/Mr
Oxygen : 0.66712/16 = 0.041695
Carbon : 0.3853/12 = 0.032108
Hydrogen : 0.05178/1 = 0.05178
Nitrogen : 0.2247/14 = 0.01605
Phosphorus : 0.2981/31 = 0.0096161

b) To get the ratio, we divide everything by the smallest number which in this case is 0.0096161.

Example : Oxygen -----> 0.041695/0.0096161 = 13/3(nearest)
So the ratio is O    : C      : H      : N     : P
                  13/3  : 10/3 : 16/3  : 5/3   : 1

Now we just have to multiply by 3 to get C₁₀O₁₃N₅H₁₆P₃. This is the empirical formula.

d) The empirical formula gives us an Mr of 494.

494n = 507 which is almost n=1.

Hence the molecular formula is equal to the empirical one.

Molecular formula : C₁₀O₁₃N₅H₁₆P₃

Thanks amillion Thanks 
but I really had too many questions there hope that u could help
ur ansers are really great I will try to do it by meslf now 

[Deadly_king]

Thanks amillion Thanks 
but I really had too many questions there hope that u could help
ur ansers are really great I will try to do it by meslf now 

No problem.

Do post your doubts and i'll try to help you as much as possible.

[The Golden Girl =D]

Thanks that is great  
how did u took the screen shot pm me   other wise I wonot be able to post my questions as they are too long to type 

u open ur CD

then open the page and zoom in , how to do the zoom in is to click on the interactive and I guess that's it .

then press on a button that says *print screen* or *screen shot*

then paste it on the Paint thingy

then save it as a JPG. file

then when u wrie a reply there is smthn at the end that says Additional Options u press that and then Attachments and then u upload it

that's it =D

[~ Miss Relina ~]

u open ur CD

then open the page and zoom in , how to do the zoom in is to click on the interactive and I guess that's it .

then press on a button that says *print screen* or *screen shot*

then paste it on the Paint thingy

then save it as a JPG. file

then when u wrie a reply there is smthn at the end that says Additional Options u press that and then Attachments and then u upload it

that's it =D

Thanks vvvv much u have made for me favour 

[The Golden Girl =D]

Thanks vvvv much u have made for me favour 

Anytime

[~ Miss Relina ~]

my second question is is this Q1:definition write or should it include 1/12th the mass of carbon-12 atom

Q2: i have attatched the table and the question

if u know what are the studies that would be needed to determine if food labelling has an impact on dietary choices??

[The Golden Girl =D]

my second question is is this Q1:definition write or should it include 1/12th the mass of carbon-12 atom

Q2: i have attatched the table and the question

if u know what are the studies that would be needed to determine if food labelling has an impact on dietary choices??

first Q , my teacher said that it has to be compared to 1/12 of a carbon12 atom .

Second Q , sorry can't help u I'm doing something else