Answer4)
hog(x) is same as hg(x)
g(x)=x/(x+1)
therefore for h(g(x)) u substitute g(x) in place of x in h(x) like this:
h(x)=2x-1 ; in place of x you subs. x/(x+1); ull get : 2x/(x+1) - 1 ; equalise the denominator by multiplyin (x+1) and multiply the numerator with (x+1) also, giving you (2x-x-1)/(x+1) = (x-1)/(x+1) .