I take it that you found the solution to part (b)
Work done by spring = 1/2 k ( x
22 - x
12)
c) You should find out the gain in strain energy of spring using the equation above. But you need to convert k in Nm
-1 first. Hence k = 1600Nm
-1Gain in energy strain energy for both springs = 1/2(1600)(0.06
2 - 0.045
2) + 1/2(1600)(0.03
2 - 0.045
2) =
0.36 J
Strain energy gets converted into kinetic energy of trolley.
K.E = 1/2mv
2 = 0.36
Taking m as 0.85kg ---->
V = 0.92 ms-1Hope it helps