ur talking about part i right? if u are, i agree what u did but if u see i also added + (10C4*9C1*14C1). This was because u can ALSO have 4 men, 1 woman and any 1 other, either man or woman.
I'm not sure of this of course, but I don't think your answer is right. I got 9828 ways. 4 men, 1 woman and 1 man/woman- this doesn't make sense. It has to have a minimum of 4 men, right? This means that the only possible combinations are 4 men-2 women and 5 men-1 woman. So the answer should be (10C4*9C2)+(10C5*9C1)= 9828
I also got 2/3 for the last answer and I don't remember my other answers to that question, but I can probably work them out later and check them with you guys.
I got 8/11 for that 6 mark question, I'm SO HAPPY that other people got that answer too! That question was extremely confusing, you had to think about it for quite a while before attempting it. This was a tough S1 paper by comparison, so threshold should be atleast 35.
My new mean and standard deviation were 52.something and 7.something, if I remember right.